Courses
Courses for Kids
Free study material
Offline Centres
More

Ram travels from P to Q at 10km/hr and returns at 15km/hr. Shyam travels from P to Q and returns at 12.5km/hr if he takes 12 minutes less than Ram then what is the distance between P and Q?
(A) 60 km
(B) 45 km
(C) 36 km
(D) 30 km

seo-qna
Last updated date: 23rd Feb 2024
Total views: 359.1k
Views today: 8.59k
IVSAT 2024
Answer
VerifiedVerified
359.1k+ views
Hint: Assume that the distance from P to Q be \[x\] km. Use the formula, Time = \[\dfrac{\text{Distance}}{\text{Speed}}\] and calculate the time taken by Ram to travel from P to Q and then, from Q to P. Similarly, calculate the time taken by Shyam to travel from P to Q and then, from Q to P. Use the information that Shyam takes 12 minutes less than Ram and form an equation. Now, solve it further and get the value of x.

Complete step-by-step solution
According to the question, we are given that Ram travels from P to Q at 10km/hr and returns at 15km/hr. Shyam travels from P to Q and returns at 12.5km/hr and he takes 12 minutes less than Ram.
First of all, let us assume that the distance from P to Q is \[x\] km.
The speed of Ram while traveling from P to Q = 10 km/hr …………………………………..(1)
Distance covered by Ram while traveling from P to Q = \[x\] km ………………………………………….(2)
We know the formula that, Time = \[\dfrac{\text{Distance}}{\text{Speed}}\] …………………………………………..(3)
Now, using equation (1), equation (2), and equation (3), we get
Time is taken by Ram to travel from P to Q = \[\dfrac{x}{10}\] hr …………………………………………(4)
The speed of Ram while returning from Q to P = 15 km/hr …………………………………..(5)
Distance covered by Ram while traveling from P to Q = \[x\] km ………………………………………….(6)
Now, from equation (3), equation (5), and equation (6), we get
Time is taken by Ram to return from Q to P = \[\dfrac{x}{15}\] hr ……………………………………………(7)
Total time taken by Ram to travel from P to Q and then return from Q to P = \[\dfrac{x}{10}+\dfrac{x}{15}=\dfrac{5x}{30}=\dfrac{x}{6}\] hr …………………………………………………(8)
The speed of Shyam while traveling from P to Q = 12.5 km/hr …………………………………..(9)
Distance covered by Shyam while traveling from P to Q = \[x\] km ………………………………………….(10)
Now, using equation (3), equation (9), and equation (10), we get
Time is taken by Shyam to travel from P to Q = \[\dfrac{x}{12.5}\] hr …………………………………………(11)
The speed of Shyam while returning from Q to P = 12.5 km/hr …………………………………..(12)
Distance covered by Shyam while traveling from P to Q = \[x\] km ………………………………………….(13)
Now, from equation (3), equation (11), and equation (12), we get
Time is taken by Shyam to return from Q to P = \[\dfrac{x}{12.5}\] hr ……………………………………………(14)
Total time taken by Ram to travel from P to Q and then return from Q to P = \[\dfrac{x}{12.5}+\dfrac{x}{12.5}=\dfrac{2x}{12.5}\] hr …………………………………………………(15)
We know the relation between hour and minutes, \[60\min =1hr\Rightarrow 1\min =\dfrac{1}{60}hr\] ……………………………………………..(16)
Now, using equation (16), let us convert 12 minutes into an hour.
 \[\Rightarrow 12\min =\dfrac{1}{60}\times 12hr\]
\[\Rightarrow 12\min =\dfrac{1}{5}hr\] ……………………………………………(17)
We are also given that Shyam takes 12 minutes less than Ram …………………………………………(18)
Now, from equation (8), equation (15), equation (17), and equation (18), we get
\[\begin{align}
  & \Rightarrow \dfrac{x}{6}=\dfrac{2x}{12.5}+\dfrac{1}{5} \\
 & \Rightarrow \dfrac{x}{6}-\dfrac{4x}{25}=\dfrac{1}{5} \\
 & \Rightarrow \dfrac{25x-24x}{6\times 25}=\dfrac{1}{5} \\
 & \Rightarrow \dfrac{x}{6\times 25}=\dfrac{1}{5} \\
\end{align}\]
\[\Rightarrow x=30\]
Therefore, the distance between P to Q is 30km. Hence, the correct option is (D).

Note: In this question, one might make a silly mistake while forming the equation using the information that Shyam takes 12 minutes less than Ram. Here, one might write the equation as \[\dfrac{x}{6}+\dfrac{1}{5}=\dfrac{2x}{12.5}\] . This is wrong. Since the time taken by Shyam is 12 minutes less than the time taken by Ram so, we have to add \[\dfrac{1}{5}\] hr to the time taken by Shyam to make it equal to the time taken by Ram.