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How many protons, neutrons, electrons, energy levels and valence electrons do Boron \[(B)\] have?

Answer
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Hint: Boron is a chemical element whose atomic number $5$ and the letter B. Boron is the lightest component with a p-orbital electron in its ground state. However, unlike the majority of other p-elements, it rarely follows the octet rule.

Complete answer:
Boron is an element that has an atomic number which is equal to $5$. So, $Z = 5$ which means that its nucleus is made up of $5$ protons which are $5$ positively charged particles.

As there are $5$ protons, the neutral atom will have $5$ electrons that revolve around the atom. Since we all know that the number of protons is always equal to the number of electrons in a neutral atom. The electronic configuration of the boron is $1{s^2}2{s^2}2{p^1}$ which shows that the valence number of electrons is $3$.

There are two typical isotopes of boron: $(i)$ ${}^{11}B$ , which has $6$ neutrons and is approximately eighty per cent naturally abundant; and $(ii)$ ${}^{10}B$ , which has $5$ neutrons. This isotopic abundance is reflected in the atomic mass of boron, $10.81g$, as listed in the Periodic Table.

Boron has $2$ energy levels as the period number of boron is $2$. Therefore, we can conclude that Boron has
$5$ protons,
$6$ neutrons and $5$ neutrons due to isotopic nature,
$5$ electrons,
$2$ energy levels, and
$3$ valence electrons

Note: Boron is a naturally occurring mineral that can be present in food and the atmosphere. Boron supplements are used as a drug. Boron is used to strengthening bones, treat osteoarthritis, develop muscles and increase testosterone levels, as well as improve reasoning abilities and muscle control.