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# Product of two integers with unlike sign is\begin{align} & \left( a \right)\text{Negative} \\ & \left( b \right)0 \\ & \left( c \right)\text{Positive} \\ & \left( d \right)\text{None of these} \\ \end{align}

Last updated date: 23rd Jul 2024
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Now we start off with the solution to the given problem by first assuming the two integers, we assume the positive integer as $a$ and the negative integer as $-b$ . After this we multiply the two integers as, $\left( +a \right)\times \left( -b \right)$ . Now we can also write this as, $ab\left( +1 \right)\times \left( -1 \right)$ . Now when we multiply any opposite signs, the result becomes negative and is equal to $-1$ . Thus here in our problem, the resultant answer would be nothing but $-ab$ , because the multiplication of $\left( +1 \right)\times \left( -1 \right)$ results in $-1$ . Now choosing the option for the answer, we see that option ‘a’ matches our answer because it is written “negative”. So our final answer is option ‘a’.