
How do you plug the inverse $\csc \left( -7/3 \right)$ into the calculator$?$
Answer
519k+ views
Hint: The concept used to solve the problem will be to reverse the trigonometric function. The trigonometric function $\csc $ is also written as $\text{cosecant}$. We need to check the domain of the inverse of the trigonometric function $\csc $. The domain of inverse $\csc $ which is represented by ${{\csc }^{-1}}$, is $\left( -\infty ,\left. -1 \right] \right.\cup \left[ 1,\left. \infty \right) \right.$.
Complete step by step solution:
The question asks us to find the inverse of $\text{cosec}\left( -7/3 \right)$ . To solve this question we can change the trigonometric function $\csc $ into any other trigonometric function. We need to firstly see the domain of the inverse function $\csc $. The domain of the trigonometric inverse of $\csc $ should be greater than equal to $1$ and less than equal to $-1$ . Mathematically for a function ${{\csc }^{-1}}a$ the value of its domain is $a$ which will be $a\ge 1$ and $a\le 1$ . Since, in this question $a=\dfrac{-7}{3}$ , this means the angle will lie between $-\dfrac{\pi }{2}$ to $\dfrac{\pi }{2}$ . On analysing the trigonometric function $\csc $ we find that it relates the best with the trigonometric function $\sin $. Now the relation between the function is:
${{\csc }^{-1}}a={{\sin }^{-1}}\left( \dfrac{1}{a} \right)$
On putting the values given in the question we get:
$\Rightarrow {{\csc }^{-1}}\left( \dfrac{-7}{3} \right)={{\sin }^{-1}}\left( \dfrac{1}{\dfrac{-7}{3}} \right)$
The value in the domain of ${{\sin }^{-1}}$ will reciprocal itself as $1$ divided by the fraction results in interchanging the numerator and denominator.
$\Rightarrow {{\csc }^{-1}}\left( \dfrac{-7}{3} \right)={{\sin }^{-1}}\left( \dfrac{-3}{7} \right)$
We know that the domain of ${{\sin }^{-1}}$ trigonometric functions from $-1$ to $+1$ including $-1$ and $1$, which is represented as $\left[ -1,1 \right]$. This means ${{\sin }^{-1}}\left( \dfrac{-3}{7} \right)$ is valid.
$\therefore $ We can find the value of ${{\csc }^{-1}}\left( \dfrac{-7}{3} \right)$ by changing it to ${{\sin }^{-1}}\left( \dfrac{-3}{7} \right)$ using calculator.
Note: We use the similar idea to find the inverse of trigonometric function $\text{secant}$ and $\text{cotanget}$ on many calculators. We should know the range of the trigonometric function and inverse trigonometric function as it helps us in knowing whether the function is used correctly or not. Sometimes to find the value of a certain trigonometric function it is changed into the different trigonometric is applied which makes solving easier.
Complete step by step solution:
The question asks us to find the inverse of $\text{cosec}\left( -7/3 \right)$ . To solve this question we can change the trigonometric function $\csc $ into any other trigonometric function. We need to firstly see the domain of the inverse function $\csc $. The domain of the trigonometric inverse of $\csc $ should be greater than equal to $1$ and less than equal to $-1$ . Mathematically for a function ${{\csc }^{-1}}a$ the value of its domain is $a$ which will be $a\ge 1$ and $a\le 1$ . Since, in this question $a=\dfrac{-7}{3}$ , this means the angle will lie between $-\dfrac{\pi }{2}$ to $\dfrac{\pi }{2}$ . On analysing the trigonometric function $\csc $ we find that it relates the best with the trigonometric function $\sin $. Now the relation between the function is:
${{\csc }^{-1}}a={{\sin }^{-1}}\left( \dfrac{1}{a} \right)$
On putting the values given in the question we get:
$\Rightarrow {{\csc }^{-1}}\left( \dfrac{-7}{3} \right)={{\sin }^{-1}}\left( \dfrac{1}{\dfrac{-7}{3}} \right)$
The value in the domain of ${{\sin }^{-1}}$ will reciprocal itself as $1$ divided by the fraction results in interchanging the numerator and denominator.
$\Rightarrow {{\csc }^{-1}}\left( \dfrac{-7}{3} \right)={{\sin }^{-1}}\left( \dfrac{-3}{7} \right)$
We know that the domain of ${{\sin }^{-1}}$ trigonometric functions from $-1$ to $+1$ including $-1$ and $1$, which is represented as $\left[ -1,1 \right]$. This means ${{\sin }^{-1}}\left( \dfrac{-3}{7} \right)$ is valid.
$\therefore $ We can find the value of ${{\csc }^{-1}}\left( \dfrac{-7}{3} \right)$ by changing it to ${{\sin }^{-1}}\left( \dfrac{-3}{7} \right)$ using calculator.
Note: We use the similar idea to find the inverse of trigonometric function $\text{secant}$ and $\text{cotanget}$ on many calculators. We should know the range of the trigonometric function and inverse trigonometric function as it helps us in knowing whether the function is used correctly or not. Sometimes to find the value of a certain trigonometric function it is changed into the different trigonometric is applied which makes solving easier.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 12 Economics: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

When was the first election held in India a 194748 class 12 sst CBSE

