
When \[Pb{(N{O_3})_2}\] is heated , the products formed are :
A . $PbO,{N_2},{O_2}$
B . $PbO,{(N{O_2})_3},{O_2}$
C . $PbO,N{O_2},{O_2}$
D . $Pb,{N_2},{O_2}$
Answer
592.5k+ views
Hint: Decomposition reaction is a reaction where a compound breaks into more substances. When we heat \[Pb{(N{O_3})_2}\] it also breaks down into simpler substances. So the heating of \[Pb{(N{O_3})_2}\] is an example of decomposition reaction.
Complete step by step solution:
The following reaction shows the decomposition and product formation on heating \[Pb{(N{O_3})_2}\],
$2Pb{(N{O_3})_2} \to 2PbO + 4N{O_2} + {O_2}$
When crystal of lead nitrate are heated it evolves brown gas (nitrogen dioxide ), oxygen gas, along with lead oxide which is a yellow residue formed at the end of the reaction .So option C is the correct which is $PbO,N{O_2},{O_2}$.
Additional information:
Lets know about some properties and uses of lead nitrate ,nitrogen dioxide, and oxygen . \[Pb{(N{O_3})_2}\] is a colourless crystal which is found in form of white powder, it is soluble in water and have molar mass $331.2gmo{l^{ - 1}}$. It is useful in manufacture of matches and explosives. Nitrogen dioxide $(N{O_2})$ is a reddish brown gas, having nasty smell which has molar mass $46.005gmo{l^{ - 1}}$. Nitrogen dioxide in the air forms the burning of fuel and forms emission from cars ,buses and trucks, power plants and other road equipment. Nitrogen dioxide is used as an indicator for the larger group of nitrogen oxide. It is one of the highly reactive gases .Oxygen is a colourless, odorless gas which has no taste .We all know how much oxygen is useful for our life as it helps in the life cycle of living things. Lead monoxide is a red or orange solid and useful in manufacture of batteries, paints etc. It is soft, malleable and has a very low melting point.
Note : When lead nitrate is heated the products formed are lead monoxide $(PbO)$, nitrogen dioxide $(N{O_2})$ and oxygen\[({O_2})\]. This is a thermal decomposition of lead nitrate \[Pb{(N{O_3})_2}\].
Complete step by step solution:
The following reaction shows the decomposition and product formation on heating \[Pb{(N{O_3})_2}\],
$2Pb{(N{O_3})_2} \to 2PbO + 4N{O_2} + {O_2}$
When crystal of lead nitrate are heated it evolves brown gas (nitrogen dioxide ), oxygen gas, along with lead oxide which is a yellow residue formed at the end of the reaction .So option C is the correct which is $PbO,N{O_2},{O_2}$.
Additional information:
Lets know about some properties and uses of lead nitrate ,nitrogen dioxide, and oxygen . \[Pb{(N{O_3})_2}\] is a colourless crystal which is found in form of white powder, it is soluble in water and have molar mass $331.2gmo{l^{ - 1}}$. It is useful in manufacture of matches and explosives. Nitrogen dioxide $(N{O_2})$ is a reddish brown gas, having nasty smell which has molar mass $46.005gmo{l^{ - 1}}$. Nitrogen dioxide in the air forms the burning of fuel and forms emission from cars ,buses and trucks, power plants and other road equipment. Nitrogen dioxide is used as an indicator for the larger group of nitrogen oxide. It is one of the highly reactive gases .Oxygen is a colourless, odorless gas which has no taste .We all know how much oxygen is useful for our life as it helps in the life cycle of living things. Lead monoxide is a red or orange solid and useful in manufacture of batteries, paints etc. It is soft, malleable and has a very low melting point.
Note : When lead nitrate is heated the products formed are lead monoxide $(PbO)$, nitrogen dioxide $(N{O_2})$ and oxygen\[({O_2})\]. This is a thermal decomposition of lead nitrate \[Pb{(N{O_3})_2}\].
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