Question

Pankaja is younger than her brother by 1460 days. If her brother was born on Sunday, what was the day on Pankaja’s birth date?
A.Sunday
B.Tuesday
C.Wednesday
D.Thursday

Answer 1

Hint: In this question, we need to determine the day of Pankaja’s birth date such that her elder brother is 1460 days older than her. For this, we will follow the concept of leap years.

Complete step-by-step answer:
In a year there are 365 days, and there are 7 days in a week.
There are 52 complete weeks in a year, and so, there is 1 odd day every common year.
Leap years are the one which has 29 days in the month of February and the total number of days in a leap year is 366. Hence, in the case of a leap year, there will be 2 odd days.
According to the question, Pankaja is 1460 days younger than her brother, so, Pankaja birth date is 1461 days earlier than her brother.
Now, 1460 can be re-written as (365+365+365+365). So, the birth date of Pankaja will be after three complete years and the last day of the corresponding leap year.
If brother’s birthday is Sunday then,
After one year, the same date will be Monday
After two years, the same date will be Tuesday
After three years, the same date would be Wednesday
At the end of the fourth year, the birthday will be on Thursday.

So, the correct answer is “Option D”.

Note: Leap year occurs after every three years. So, we can say that every fourth year is a leap year. It is interesting to note here that the year number which is completely divisible by 4 is the leap year.