
Ozone reacts with lead sulfide.
A) True
B) False
Answer
498.6k+ views
Hint: The lead sulfide is a reagent which has molecular formula as ${\text{PbS}}$ and ozone has molecular formula as ${O_3}$. One can think about the possible reaction that can happen between them and if lead sulfate can get oxidized by ozone.
Complete step by step answer:
1) First of all we will discuss the ozone as a reagent. The ozone is a reagent that is used as a strong oxidizing agent in many chemical reactions.
2) Ozone has a molecular formula ${O_3}$ that has three oxygen atoms in its molecule hence, it is a very strong oxidizing agent. Now let's discuss the reagent lead sulfate in which the lead is in the oxidation state II and has a molecular formula as ${\text{PbS}}$.
3) Now let us see the reaction of the lead sulfide with the ozone as below,
$PbS + 4{O_3}\xrightarrow{{}}PbS{O_4} + 4{O_2}$
In the above reaction when lead sulfide is reacted with the ozone then there is a formation of lead sulfate and the four moles of oxygen molecule.
4) Therefore, as in the above reaction the lead sulfide is reacted with ozone we can say that the statement ozone reacts with lead sulfide is true which shows option A as the correct choice of answer.
And hence option A is the correct answer.
Note:
In lead sulfide, the suffix sulfide shows that the sulfur is an anion which is ${S^{ - 2}}$ and it also gives the oxidation state of the lead as ${\text{ + 2}}$. In the case of the lead sulfate, the suffix sulfide shows the group as $S{O_4}^{ - 2}$. Whenever the reaction with the ozone happens there is an oxidation reaction which means the addition of an oxygen atom.
Complete step by step answer:
1) First of all we will discuss the ozone as a reagent. The ozone is a reagent that is used as a strong oxidizing agent in many chemical reactions.
2) Ozone has a molecular formula ${O_3}$ that has three oxygen atoms in its molecule hence, it is a very strong oxidizing agent. Now let's discuss the reagent lead sulfate in which the lead is in the oxidation state II and has a molecular formula as ${\text{PbS}}$.
3) Now let us see the reaction of the lead sulfide with the ozone as below,
$PbS + 4{O_3}\xrightarrow{{}}PbS{O_4} + 4{O_2}$
In the above reaction when lead sulfide is reacted with the ozone then there is a formation of lead sulfate and the four moles of oxygen molecule.
4) Therefore, as in the above reaction the lead sulfide is reacted with ozone we can say that the statement ozone reacts with lead sulfide is true which shows option A as the correct choice of answer.
And hence option A is the correct answer.
Note:
In lead sulfide, the suffix sulfide shows that the sulfur is an anion which is ${S^{ - 2}}$ and it also gives the oxidation state of the lead as ${\text{ + 2}}$. In the case of the lead sulfate, the suffix sulfide shows the group as $S{O_4}^{ - 2}$. Whenever the reaction with the ozone happens there is an oxidation reaction which means the addition of an oxygen atom.
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