Question

Oxidation state of nitrogen in $$[Co{(N{H}_3)}_{5}Cl]C{l}_2$$ is –x. The value of x is:

Answer 1

Hint: In coordination complexes few ligands have charge called as charged ligands and few ligands don’t have charge called as neutral ligands. Ammonia is a neutral ligand. And chlorine is a charged ligand.

Complete step by step answer:
-The nitrogen in the given coordination compound is present in the form of ammonia.
To find the oxidation of nitrogen in the given compound, the element attached to it must be identified.
-Nitrogen is a non-metal, when hydrogen is attached to a non-metal it has a charge of “1”.
In the case of the given coordination compound the sum of the oxidation number of all the individual elements present in the compound equals to zero.
-Let us imagine the oxidation state of nitrogen being -x.
Then
x+(3)=0
x= -3

In the question it was mentioned that the oxidation number of nitrogen is “–x”.
So, the value of x is “3”.
Thus the oxidation state of nitrogen in $$[Co{(N{H}_3)}_{5}Cl]C{l}_2$$ is identified as “-3”.
The oxidation state of cobalt metal in $$[Co{(N{H}_3)}_{5}Cl]C{l}_2$$is “+3”.

Note: Don’t be confused with the words oxidation state and oxidation number. Both are the same.
“Oxidation number, also called Oxidation State. The total number of electrons that an atom either gains or losses in order to form a chemical bond with another atom is called oxidation number”.