
One way of writing the equation of state for heat gases is \[PV=RT\left[ 1+\dfrac{B}{V}+...... \right]\] where B is constant. An approximate expression for ’ B’ in terms of van der Waals constant ‘a’ and ‘b’ is:
A. $b+a/RT$
B. $b-a/RT$
C. $b+a/2RT$
D. $a+b/RT$
Answer
573.9k+ views
Hint: According to the ideal gas law, the molecules of a gas are point particles with perfectly elastic collisions since gas particles aren’t point particles, a modification in the ideal gas law was done.
Ideal gas law before modification: \[PV=nRT\] and after modification
\[\left( P+\dfrac{a}{{{V}^{2}}} \right)\left( V-b \right)=RT\]
Where a, b are constants; P = pressure
V = Volume, T = Temp and R = constant
Complete step by step answer:
According to the modified Van Der Wall’s equation, we have
\[\Rightarrow \left( P+\dfrac{a}{{{V}^{2}}} \right)\left( V-b \right)=RT\]
\[\Rightarrow P+\dfrac{a}{{{V}^{2}}}=\dfrac{RT}{V-b}\]
\[\Rightarrow P=\dfrac{RT}{V-b}-\dfrac{\alpha }{{{V}^{2}}}\]
\[\Rightarrow \dfrac{P}{RT}=\dfrac{1}{V-b}-\dfrac{a}{{{V}^{2}}RT}\]
\[\Rightarrow \dfrac{V}{RT}=\dfrac{1}{\dfrac{V-b}{V}}-\dfrac{a}{VRT}\]
\[\Rightarrow \dfrac{PV}{RT}=\dfrac{1}{1-\dfrac{b}{V}}-\dfrac{a}{VRT}......................\text{(i) }\]
We know the binomial expansion:
\[\left( \dfrac{1}{1-x} \right)=1+x+{{x}^{2}}+{{x}^{3}}+.......\]
Expanding equation 1 with the same binomial expansion we get,
\[\Rightarrow \dfrac{RV}{RT}=\left( 1+\dfrac{b}{V}+\dfrac{{{b}^{2}}}{{{V}^{2}}}+......... \right)-\dfrac{a}{VRT}\]
\[\Rightarrow \dfrac{PV}{RT}=1+\left( b-\dfrac{a}{RT} \right)\dfrac{1}{V}+\dfrac{{{b}^{2}}}{{{V}^{2}}}+.........\text{ }\left( ii \right)\]
Comparing equation 2 with the equation give in this question we get,
\[B=b-\dfrac{a}{RT}\]
At fixed temperature the Vander Waals equation describes the relation between pressure (P), volume (V) and Temperature (T).
So, the correct answer is “Option B”.
Note: 1. At a critical temperature, the gas is characterized by the critical values of \[{{T}_{k}},{{P}_{k}}\] and \[{{V}_{k}}\] which are determined only by the gas properties.
2. Vander Waals define the physical state of a homogeneous gas, is a modification of the ideal gas equation and moves nearly describes the properties of actual glass.
3. The Vander Waals equation corrects the ideal gas law for two major points. That is
(a) Excluded volume of gas particles.
(b) Alternative forces between gas molecules .
Ideal gas law before modification: \[PV=nRT\] and after modification
\[\left( P+\dfrac{a}{{{V}^{2}}} \right)\left( V-b \right)=RT\]
Where a, b are constants; P = pressure
V = Volume, T = Temp and R = constant
Complete step by step answer:
According to the modified Van Der Wall’s equation, we have
\[\Rightarrow \left( P+\dfrac{a}{{{V}^{2}}} \right)\left( V-b \right)=RT\]
\[\Rightarrow P+\dfrac{a}{{{V}^{2}}}=\dfrac{RT}{V-b}\]
\[\Rightarrow P=\dfrac{RT}{V-b}-\dfrac{\alpha }{{{V}^{2}}}\]
\[\Rightarrow \dfrac{P}{RT}=\dfrac{1}{V-b}-\dfrac{a}{{{V}^{2}}RT}\]
\[\Rightarrow \dfrac{V}{RT}=\dfrac{1}{\dfrac{V-b}{V}}-\dfrac{a}{VRT}\]
\[\Rightarrow \dfrac{PV}{RT}=\dfrac{1}{1-\dfrac{b}{V}}-\dfrac{a}{VRT}......................\text{(i) }\]
We know the binomial expansion:
\[\left( \dfrac{1}{1-x} \right)=1+x+{{x}^{2}}+{{x}^{3}}+.......\]
Expanding equation 1 with the same binomial expansion we get,
\[\Rightarrow \dfrac{RV}{RT}=\left( 1+\dfrac{b}{V}+\dfrac{{{b}^{2}}}{{{V}^{2}}}+......... \right)-\dfrac{a}{VRT}\]
\[\Rightarrow \dfrac{PV}{RT}=1+\left( b-\dfrac{a}{RT} \right)\dfrac{1}{V}+\dfrac{{{b}^{2}}}{{{V}^{2}}}+.........\text{ }\left( ii \right)\]
Comparing equation 2 with the equation give in this question we get,
\[B=b-\dfrac{a}{RT}\]
At fixed temperature the Vander Waals equation describes the relation between pressure (P), volume (V) and Temperature (T).
So, the correct answer is “Option B”.
Note: 1. At a critical temperature, the gas is characterized by the critical values of \[{{T}_{k}},{{P}_{k}}\] and \[{{V}_{k}}\] which are determined only by the gas properties.
2. Vander Waals define the physical state of a homogeneous gas, is a modification of the ideal gas equation and moves nearly describes the properties of actual glass.
3. The Vander Waals equation corrects the ideal gas law for two major points. That is
(a) Excluded volume of gas particles.
(b) Alternative forces between gas molecules .
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