One molecule of a substance absorbs one quantum of energy. The energy involved when $1.5{\text{ moles}}$ of the substance absorbs red light of frequency $7.5 \times {10^{14}}{\sec ^{ - 1}}$ will it be?
(A). $4.49 \times {10^5}J$
(B). $2.24 \times {10^5}J$
(C). $9.23 \times {10^7}J$
(D). $2.24 \times {10^7}J$
Answer
640.8k+ views
Hint:
The particle-like packets of light containing energy, charge or momentum is called photons, a term also applicable to quanta. A photon is said to be a quantum of light. A quanta is a minimum amount of any physical entity involved in an interaction.
Complete step by step answer:
Energy of red light $ = 7.5 \times {10^{14}}{\sec ^{ - 1}}$
(As given in the question)
Energy of one quantum of red light is .
$ = 6.626 \times {10^{ - 34}} \times 7.5 \times {10^{14}}$
$ = 4.9 \times {10^{ - 19}}J$
Numbers of molecules in $1{\text{ mole = 6}}{\text{.022}} \times {10^{23}}$
Energy absorbed by $1{\text{ }}\operatorname{molecule} \approx 5 \times {10^{ - 19}}J$
We know that,
1 mole contains ${\text{ = 6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{23}}$ molecules.
So $1.5$ mole contains ${\text{ = 1}}{\text{.5}} \times {\text{6}}{\text{.022}} \times {10^{23}}$ molecules.
So energy absorbed by $1.5 \times 6.022 \times {10^{23}}$ molecules.
$ = 4.9 \times {10^{ - 19}} \times 6.022 \times {10^{23}} \times 1.5$
$ = 4.4 \times {10^5}J$
Hence, (A) option is the correct one.
Additional Information:
-The quantization of energy refers to the fact that at subatomic levels, energy is best thought of as occurring in discrete ‘packets’ called photons.
-Photons are packages of energy and correspond to different types of electromagnetic radiation.
-The formula is $E = hf$ where $E$ is energy $f$ is frequency and $h$ is ting constant called planck's constant $\left( {6.62 \times {{10}^{ - 36}}\dfrac{{{m^2}kg}}{{\sec }}} \right)$
-This constant regulates and quantized the energy of the universe.
Note: Light is wave, it nevertheless exists in discrete (distinct, countable and indivisible) units i.e. particles. Light is made up of photons. That’s why it means that light is quantized.
The particle-like packets of light containing energy, charge or momentum is called photons, a term also applicable to quanta. A photon is said to be a quantum of light. A quanta is a minimum amount of any physical entity involved in an interaction.
Complete step by step answer:
Energy of red light $ = 7.5 \times {10^{14}}{\sec ^{ - 1}}$
(As given in the question)
Energy of one quantum of red light is .
$ = 6.626 \times {10^{ - 34}} \times 7.5 \times {10^{14}}$
$ = 4.9 \times {10^{ - 19}}J$
Numbers of molecules in $1{\text{ mole = 6}}{\text{.022}} \times {10^{23}}$
Energy absorbed by $1{\text{ }}\operatorname{molecule} \approx 5 \times {10^{ - 19}}J$
We know that,
1 mole contains ${\text{ = 6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{23}}$ molecules.
So $1.5$ mole contains ${\text{ = 1}}{\text{.5}} \times {\text{6}}{\text{.022}} \times {10^{23}}$ molecules.
So energy absorbed by $1.5 \times 6.022 \times {10^{23}}$ molecules.
$ = 4.9 \times {10^{ - 19}} \times 6.022 \times {10^{23}} \times 1.5$
$ = 4.4 \times {10^5}J$
Hence, (A) option is the correct one.
Additional Information:
-The quantization of energy refers to the fact that at subatomic levels, energy is best thought of as occurring in discrete ‘packets’ called photons.
-Photons are packages of energy and correspond to different types of electromagnetic radiation.
-The formula is $E = hf$ where $E$ is energy $f$ is frequency and $h$ is ting constant called planck's constant $\left( {6.62 \times {{10}^{ - 36}}\dfrac{{{m^2}kg}}{{\sec }}} \right)$
-This constant regulates and quantized the energy of the universe.
Note: Light is wave, it nevertheless exists in discrete (distinct, countable and indivisible) units i.e. particles. Light is made up of photons. That’s why it means that light is quantized.
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