Answer
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Hint: Try to recall that on an industrial scale ${H_2}{O_2}$ is prepared from an organic compound which is a derivative of anthraquinone and also, it is a pale yellow solid. Now, by using this you can easily find the correct option from the given options.
Complete step by step solution:
It is known to you that commercially ${H_2}{O_2}$ is prepared by autoxidation of an organic compound which is a derivative of anthraquinone.
The organic compound which is a derivative of anthraquinone is 2-ethylanthraquinol.
Hydrogen peroxide is prepared by autoxidation of 2-ethylanthraquinol. It involves oxidation of 2-ethylanthraquinol. The reaction is:
2-ethylanthraquinol is prepared by the reduction of 2-ethylanthraquinone by ${H_2}$ in the presence of palladium.
Therefore, from above we can easily conclude that option A is the correct option to the given question.
Additional information:
Preparation of ${H_2}{O_2}$ by autoxidation of 2-ethylanthraquinol:
First, air is passed through a mixture of 2-ethylanthraquinol mixture in cyclohexane and benzene.
It yields 2-ethylanthraquinone and hydrogen peroxide.
The product, 2-ethylanthraquinone is then reduced. For this, hydrogen under a pressure of 1-3 atmospheres at 4 degree Celsius is passed over 2-ethylanthraquinone in the presence of a Pd catalyst.
This gives back the reactant - 2-ethylanthraquinol.
The ${H_2}{O_2}$ is extracted with water and the solution of required concentration is obtained.
Note: It should be remembered to you that in the autoxidation of 2-ethylanthraquinol, only atmospheric oxygen and hydrogen are used which are inexpensive. Hence, this method is widely used for the preparation of hydrogen peroxide as it is quite cheap.
Complete step by step solution:
It is known to you that commercially ${H_2}{O_2}$ is prepared by autoxidation of an organic compound which is a derivative of anthraquinone.
The organic compound which is a derivative of anthraquinone is 2-ethylanthraquinol.
Hydrogen peroxide is prepared by autoxidation of 2-ethylanthraquinol. It involves oxidation of 2-ethylanthraquinol. The reaction is:
2-ethylanthraquinol is prepared by the reduction of 2-ethylanthraquinone by ${H_2}$ in the presence of palladium.
Therefore, from above we can easily conclude that option A is the correct option to the given question.
Additional information:
Preparation of ${H_2}{O_2}$ by autoxidation of 2-ethylanthraquinol:
First, air is passed through a mixture of 2-ethylanthraquinol mixture in cyclohexane and benzene.
It yields 2-ethylanthraquinone and hydrogen peroxide.
The product, 2-ethylanthraquinone is then reduced. For this, hydrogen under a pressure of 1-3 atmospheres at 4 degree Celsius is passed over 2-ethylanthraquinone in the presence of a Pd catalyst.
This gives back the reactant - 2-ethylanthraquinol.
The ${H_2}{O_2}$ is extracted with water and the solution of required concentration is obtained.
Note: It should be remembered to you that in the autoxidation of 2-ethylanthraquinol, only atmospheric oxygen and hydrogen are used which are inexpensive. Hence, this method is widely used for the preparation of hydrogen peroxide as it is quite cheap.
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