Answer
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Hint: To obtain the equation of line from the position of points lying on the line, we can use the formula-
$\mathrm y-{\mathrm y}_1=\dfrac{{\mathrm y}_2-{\mathrm y}_1}{{\mathrm x}_2-{\mathrm x}_1}\left(\mathrm x-{\mathrm x}_1\right)$
Complete step-by-step answer:
The line and four points are given as follows-
Let us take the line parallel to y axis with four points on the line as A(5,1) , B(5,2) ,C(5,5) and D(5,6)
To find the equation of line, only two points are required. So, we can choose any two points randomly to find the equation of line. Using points A and B,
$\mathrm y-1=\dfrac{2-1}{5-5}\left(\mathrm x-5\right)\\0\left(\mathrm y-1\right)=\mathrm x-5\\\mathrm x=5$
This is the equation of the line. The other two points C(5,5) and D(5,6.5) also satisfy the equation of the line.
Note: If we assume any other points like C and D, we will get the same equation as in the answer. Students should take care that they draw the key and mark the axes correctly on the graph sheet.
$\mathrm y-{\mathrm y}_1=\dfrac{{\mathrm y}_2-{\mathrm y}_1}{{\mathrm x}_2-{\mathrm x}_1}\left(\mathrm x-{\mathrm x}_1\right)$
Complete step-by-step answer:
The line and four points are given as follows-
Let us take the line parallel to y axis with four points on the line as A(5,1) , B(5,2) ,C(5,5) and D(5,6)
To find the equation of line, only two points are required. So, we can choose any two points randomly to find the equation of line. Using points A and B,
$\mathrm y-1=\dfrac{2-1}{5-5}\left(\mathrm x-5\right)\\0\left(\mathrm y-1\right)=\mathrm x-5\\\mathrm x=5$
This is the equation of the line. The other two points C(5,5) and D(5,6.5) also satisfy the equation of the line.
Note: If we assume any other points like C and D, we will get the same equation as in the answer. Students should take care that they draw the key and mark the axes correctly on the graph sheet.
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