
When an object is placed between F and 2F, in front of a convex lens, the image formed is:
A.)Real and Inverted
B.)Beyond 2F
C.)Magnified
D.)All of the above
Answer
590.7k+ views
Hint: The image formed by a convex lens depends on the position where the object is placed. Usually a convex lens forms a real image.
Complete step by step answer:
We know that the convex lens is a converging lens so the light rays after passing through the lens converges to a point called focus. So when an object AB is placed at a distance between F and 2F, the image will be at a distance greater than 2F (beyond 2F) from the right side.
The linear magnification (m) of a lens is given by the equation,
$\text{m}=\dfrac{v}{u}$
Where,
v is the distance of the image from the lens, which is positive in this case, since distances from the right side of the mirror are taken as positive.
u is the distance of the object from the lens, which is negative in this case, since distance from the left side of the mirror is taken as negative.
(i)Since the image distance (v) is greater than the object distance (u) in our case, we will get a magnification greater than 1 with a negative sign.
(ii)The negative sign indicates that the object is inverted.
(iii)So the image formed is real, inverted and magnified.
So the answer to the question is option (D)- All of the above.
Note: If the object was placed at a distance greater than 2F, the image will be formed between F and 2F on the right side of the lens.
If the object is placed at a distance at F from the lens, the image will be formed at a distance F on the right side of the lens.
Complete step by step answer:
We know that the convex lens is a converging lens so the light rays after passing through the lens converges to a point called focus. So when an object AB is placed at a distance between F and 2F, the image will be at a distance greater than 2F (beyond 2F) from the right side.
The linear magnification (m) of a lens is given by the equation,
$\text{m}=\dfrac{v}{u}$
Where,
v is the distance of the image from the lens, which is positive in this case, since distances from the right side of the mirror are taken as positive.
u is the distance of the object from the lens, which is negative in this case, since distance from the left side of the mirror is taken as negative.
(i)Since the image distance (v) is greater than the object distance (u) in our case, we will get a magnification greater than 1 with a negative sign.
(ii)The negative sign indicates that the object is inverted.
(iii)So the image formed is real, inverted and magnified.
So the answer to the question is option (D)- All of the above.
Note: If the object was placed at a distance greater than 2F, the image will be formed between F and 2F on the right side of the lens.
If the object is placed at a distance at F from the lens, the image will be formed at a distance F on the right side of the lens.
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