Question

Number which is divisible by $2$ is
A. $7907$
B. $63195$
C. $72028$
D. $3451$

Answer 1

Hint: For solving these problems, we need to have a clear understanding of odd and even numbers and the divisibility test for $2$ . By employing the divisibility test, we can check the options one by one and thus get the number which is divisible by $2$ .

Complete step by step solution:
Different numbers have different divisibility tests. For example, the divisibility test for a number to be divisible by $3$ is that the sum of the digits of the number must be a multiple of $3$ . Also, we know that the divisibility test of $2$ states that a number is divisible by $2$ if the last digit of the number is even and even numbers are multiples of $2$ . A number is even if it ends in \[0,2,4,6,\text{ }or\text{ }8\] . Now, consider the number \[72028\] , the last digit of the number is $8$ which is an even number. The last number of \[7907\] is $7$ which is an odd number, hence it is not divisible by $2$ . The last number of $63195$ is $5$ which is an odd number, hence it is not divisible by $2$ . The last number of $3451$ is $1$ which is an odd number, hence it is not divisible by $2$ . Therefore, $72028$ is divisible by $2$ because the last digit is $8$ which is an even number.
Hence, the number $72028$ is divisible by $2$ .

So, the correct answer is “Option C”.

Note: These problems may seem easy but one has to be very clear about the concept of odd and even numbers. A slight misjudgement can lead to an incorrect answer. One also needs to be clear about the divisibility test of numbers for solving these kinds of problems.