Number of carbon atoms present in 22g $C{O_2}$ is
A.$6.02 \times {10^{23}}$
B.$3.01 \times {10^{^{23}}}$
C.$3.01 \times {10^{^{ - 23}}}$
D.$6.02 \times {10^{ - 23}}$
Answer
545.3k+ views
Hint:An atom is the smallest unit of matter that forms chemical elements. Every solid, liquid, gas is composed of atoms. An atom consists of atomic number and atomic mass. Atoms form molecules. We shall calculate the number of moles in the given weight and multiply it with Avogadro’s number to find the number of molecules in it.
Formula Used: ${\text{Moles of a substance = }}\dfrac{{{\text{Weight of substance}}}}{{{\text{Molecular mass of substance}}}}$
Complete step by step answer:
The mole (symbol: mol) is the unit of measurement for quantity of substance in the International System of Units. The mole is widely used in chemistry as a convenient way to tell the quantity of reactants and products of a chemical reaction. It is used to calculate the amount of a substance.
For 22g of carbon dioxide,
${\text{Moles of carbon dioxide = }}\dfrac{{{\text{Weight of carbon dioxide}}}}{{{\text{Molecular mass of carbon dioxide}}}}$
Molecular mass of carbon dioxide is 44 g.
Hence, ${\text{Moles of carbon dioxide = }}\dfrac{{22}}{{44}}{\text{ = }}\dfrac{1}{2}$
Now, 1 mole of carbon dioxide contains $6.02 \times {10^{23}}$ molecules of carbon dioxide. As a single molecule of carbon dioxide contains 1 atom of carbon, that is why, $6.02 \times {10^{23}}$ molecules of carbon dioxide will contain $6.02 \times {10^{23}}$ atoms of carbon.
As one mole of carbon dioxide contains $6.02 \times {10^{23}}$ atoms of carbon, half mole of carbon dioxide will contain half of the $6.02 \times {10^{23}}$ atoms of carbon and that will be equal to $3.01 \times {10^{^{23}}}$ carbon atoms.
Therefore, 22 g of carbon dioxide will contain $3.01 \times {10^{^{23}}}$ carbon atoms, which is option B.
Note:
$6.02 \times {10^{23}}$ is the Avogadro number. Avogadro's law is an experimental gas law relating the volume of a gas to the amount of substance of gas present. Avogadro's law states at the same temperature and pressure, equal volumes of gases have the same number of molecules. For a given mass of an ideal gas, the moles and volume of the gas are directly proportional if the pressure and temperature are constant.
Formula Used: ${\text{Moles of a substance = }}\dfrac{{{\text{Weight of substance}}}}{{{\text{Molecular mass of substance}}}}$
Complete step by step answer:
The mole (symbol: mol) is the unit of measurement for quantity of substance in the International System of Units. The mole is widely used in chemistry as a convenient way to tell the quantity of reactants and products of a chemical reaction. It is used to calculate the amount of a substance.
For 22g of carbon dioxide,
${\text{Moles of carbon dioxide = }}\dfrac{{{\text{Weight of carbon dioxide}}}}{{{\text{Molecular mass of carbon dioxide}}}}$
Molecular mass of carbon dioxide is 44 g.
Hence, ${\text{Moles of carbon dioxide = }}\dfrac{{22}}{{44}}{\text{ = }}\dfrac{1}{2}$
Now, 1 mole of carbon dioxide contains $6.02 \times {10^{23}}$ molecules of carbon dioxide. As a single molecule of carbon dioxide contains 1 atom of carbon, that is why, $6.02 \times {10^{23}}$ molecules of carbon dioxide will contain $6.02 \times {10^{23}}$ atoms of carbon.
As one mole of carbon dioxide contains $6.02 \times {10^{23}}$ atoms of carbon, half mole of carbon dioxide will contain half of the $6.02 \times {10^{23}}$ atoms of carbon and that will be equal to $3.01 \times {10^{^{23}}}$ carbon atoms.
Therefore, 22 g of carbon dioxide will contain $3.01 \times {10^{^{23}}}$ carbon atoms, which is option B.
Note:
$6.02 \times {10^{23}}$ is the Avogadro number. Avogadro's law is an experimental gas law relating the volume of a gas to the amount of substance of gas present. Avogadro's law states at the same temperature and pressure, equal volumes of gases have the same number of molecules. For a given mass of an ideal gas, the moles and volume of the gas are directly proportional if the pressure and temperature are constant.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

