Question

What is the number in the START box? $START \to \div 16 \to \times 20 \to 132820$
$A)116256$
$B)106256$
$C)384120$
$D)102656$

Answer 1

Hint: First, we need to know about the concept of the basic operations in mathematics.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to the number from multiplying the first number. Have a look at an example; while multiplying $5 \times 7$ the number $5$ is called the multiplicand and the number $7$is called the multiplier. Like $363 \times (1560) = 566280$
The process of the inverse of the multiplication method is called division. Like $x \times y = z$ is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $\dfrac{{1560}}{{363}} = 4.29$

Complete step by step answer:
Since from given that we have to find the unknown number which divides the $16$ and then multiplied by the number $20$ which will need to make a number exactly as $132820$
Let us make the given $START \to \div 16 \to \times 20 \to 132820$ in mathematically as $\dfrac{{START}}{{16}} \times 20 = 132820$
Since START is the one value unknown so make the START left side and all other values in the right sides we get $\dfrac{{START}}{{16}} \times 20 = 132820 $
$\Rightarrow START = \dfrac{{132820}}{{20}} \times 16$ (the inverse process of the multiplication while changing the position of the values)
From the division operation, we get $START = 6641 \times 16$
Thus, from the multiplication operation, we have $START = 6641 \times 16 $
$\Rightarrow START = 106256$

So, the correct answer is “Option B”.

Note:
While changing the values we get the inverse process like $x \times y = 1 \Rightarrow x = \dfrac{1}{y}$ and $x = \dfrac{1}{y} \Rightarrow xy = 1$
The other two operations are addition and subtraction.
The addition is the summing of two or more than two numbers, or terms, or values, or variables and in addition, if we sum the two or more numbers a new frame of the number will be found, also in subtraction which is the minus of two or more than two numbers or values example $2 - 3 = - 1$ (larger number signs stays constant)