Question

What number comes just before the product of the place value of $2$ in $729$ and the face value of $3$ in $135$ ?

Answer 1

Hint: First, we need to know about the concept of place value and face value.
The place value describes the position or place of a digit in a given number. each of the digits of the number has a value depending on its place. Place value of the digit can be calculated by the face value times of the numerical value of the place.
The face value of a digit describes the value of the digit itself. It does not depend on which position or place of the digit in a number. The face value of a digit equals the numerical value of the digits themselves.

Complete step-by-step solution:
Since from the given we have place value is given as $729$ and face value is given as $135$
Hence the place of $729$ can be expressed as
Place of the third digit $9 = 9$
Place value of the second digit $2 = 2 \times 10$
Place value of the unit digit $7 = 7 \times 100$
Also, the face value of the $135$ can be expressed as
Face value of the third digit $5 = 5$
For the second digit we have $3 = 3$ and for the unit digit we have $1 = 1$
Hence from given we need to find the product of place value of $2$ in $729$ and the face value of $3$ in $135$
This means we need to take the product of $20,3$ respect to their place and face values.
Hence, we get $20 \times 3 = 60$
But there were ask us to find the number comes just before the product and thus we get $60 - 1 = 59$
Therefore, the required number is $59$.

Note: The concept of the place value that counting of the place of any digit starts from the end digits of the given numbers
The place value of the digit zero in a given number is always expressed as zero. The place value of the digit is zero.
Face value of the digit is the exact value of the number itself