
What is the net electric charge on the charged capacitor?
Answer
554.4k+ views
Hint: Capacitor is the passive electronic device that is made of the two plates which is used for storing the energy in it without the dissipation of the energy outside the circuit. The two plates possess the equal amount of the oppositely charged particles.
Complete answer:
Capacitor is the electric device that consists of one plate that is positively charged and the other plate which is negatively charged. These two plates are separated by some distance to constitute the capacitor. These two plates have the same amount of the opposite charges. The total amount of the charges that is the net charge in the capacitor is the sum of the charges in the two plates of the capacitor.
If these two plates are farther apart, the attraction does not take place making the capacitor not work by dissipating the energy from it. Let us consider that one plate of the capacitor has the $500$ positive charge and the other plate has the $500$ negative charges. These two plates are separated by the small distance $d$ constitute the capacitor. The net charge is calculated as follows.
${Q_{net}} = {Q_1} + {Q_2}$
Substituting the total number of the charges in the above step,
${Q_{net}} = 500 + \left( { - 500} \right) = 0$
Hence the net electric charge on the charged capacitor is always zero.
Note:
Remember the fact how the electrical energy is stored in the capacitor. The plates possess the opposite charged particles, the closeness of the plate causes the charges from the plate to attract each other allowing it to store more charges for a certain voltage. The unit of the capacitance is farad, it deals with the one coulomb of charge making one voltage across the device.
Complete answer:
Capacitor is the electric device that consists of one plate that is positively charged and the other plate which is negatively charged. These two plates are separated by some distance to constitute the capacitor. These two plates have the same amount of the opposite charges. The total amount of the charges that is the net charge in the capacitor is the sum of the charges in the two plates of the capacitor.
If these two plates are farther apart, the attraction does not take place making the capacitor not work by dissipating the energy from it. Let us consider that one plate of the capacitor has the $500$ positive charge and the other plate has the $500$ negative charges. These two plates are separated by the small distance $d$ constitute the capacitor. The net charge is calculated as follows.
${Q_{net}} = {Q_1} + {Q_2}$
Substituting the total number of the charges in the above step,
${Q_{net}} = 500 + \left( { - 500} \right) = 0$
Hence the net electric charge on the charged capacitor is always zero.
Note:
Remember the fact how the electrical energy is stored in the capacitor. The plates possess the opposite charged particles, the closeness of the plate causes the charges from the plate to attract each other allowing it to store more charges for a certain voltage. The unit of the capacitance is farad, it deals with the one coulomb of charge making one voltage across the device.
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