
What is the nature of an image formed by a concave mirror if the magnification produced by the mirror is $ + 3$ .
Answer
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Hint: A concave mirror is also known as a converging mirror which has a reflecting surface away from the incident light. This mirror is used to focus light and there are a number of uses in our day to day life. It produces different images at different distances like position of object at focus image at infinity and vice versa.
Complete step by step solution:
A concave mirror which is also known as a converging mirror has its reflecting surface away from the incident light. It is used during shaving to get an erect and enlarged image of the face, it is also used as a torch to reflect the light.
A concave mirror shows different image types depending on the distance between the mirror and the object.
Magnification of an object can be calculated as image size divided by the object size.
It can be also expressed as the ratio of the distance of the image i.e. $v$ to the distance of object from the mirror i.e. $u$.
Now ,
$M = \dfrac{{ - v}}{u}$
Where,
M= Magnification of the image
V=Distance of the image from the mirror
U=Distance of the object from the mirror
Here v is negative as it is present in the negative x-axis of the mirror, this will only happen if we consider the object will be at positive x-axis.
Since the value of magnification has a position value the image formed will be virtual and erect.
As given in the problem, the value of magnification is $ + 3$,therefore the image that will be formed will be of the virtual and erect.
Note:
Take proper Cartesian coordinates to get an accurate answer and learn the image position for different object positions. Also remember all the position of the image with respect to its object position and nature of the image formed by the mirror or else you will commit a mistake.
Complete step by step solution:
A concave mirror which is also known as a converging mirror has its reflecting surface away from the incident light. It is used during shaving to get an erect and enlarged image of the face, it is also used as a torch to reflect the light.
A concave mirror shows different image types depending on the distance between the mirror and the object.
Magnification of an object can be calculated as image size divided by the object size.
It can be also expressed as the ratio of the distance of the image i.e. $v$ to the distance of object from the mirror i.e. $u$.
Now ,
$M = \dfrac{{ - v}}{u}$
Where,
M= Magnification of the image
V=Distance of the image from the mirror
U=Distance of the object from the mirror
Here v is negative as it is present in the negative x-axis of the mirror, this will only happen if we consider the object will be at positive x-axis.
Since the value of magnification has a position value the image formed will be virtual and erect.
As given in the problem, the value of magnification is $ + 3$,therefore the image that will be formed will be of the virtual and erect.
Note:
Take proper Cartesian coordinates to get an accurate answer and learn the image position for different object positions. Also remember all the position of the image with respect to its object position and nature of the image formed by the mirror or else you will commit a mistake.
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