Question

Name the process associated with the following:
A potassium permanganate crystal is in a beaker and water is poured into the beaker with stirring.

Answer 1

Hint: To solve this question we first need to know what physical changes take place. When water is poured in a beaker containing potassium permanganate ($KMn{{O}_{4}}$) crystals with constant stirring, the water in the beaker turns into a deep purple-colored solution, same as the color of the crystals.

Complete answer:
When water is poured in a beaker containing potassium permanganate ($KMn{{O}_{4}}$) crystals with constant stirring, an aqueous solution is formed.
In an aqueous solution, the potassium permanganate ($KMn{{O}_{4}}$) crystals break into their consisting ions, potassium cation (${{K}^{+}}$) and permanganate anion ($MnO_{4}^{-}$).
\[KMn{{O}_{4}}(s)\xrightarrow{{{H}_{2}}O}{{K}^{+}}(aq)+MnO_{4}^{-}(aq)\]
This permanganate anion ($MnO_{4}^{-}$) imparts a deep purple color to the aqueous solution and hence upon stirring the entire solution in the beaker turns into a deep purple.
This process is known as dissolution.
The process of the addition of a solute which is dissolvable into a solvent to make a solution is known as dissolution.
Now, as the amount of water poured into the beaker is increased, the solution becomes more and more diluted, and hence the intensity of the deep purple color decreases.

Note:
It should be noted that when potassium permanganate ($KMn{{O}_{4}}$) crystals are placed in a beaker containing water, first a dense purple solution is formed at the base of the beaker which slowly spreads to the entire beaker. This process is known as diffusion.