How many moles of lead are in \[1.50 \times {10^{12}}\] atoms of lead?
Answer
577.8k+ views
Hint: We know that this is a calculation based question. Before proceeding to the calculation we have to note that actually atoms do not contain moles. A mole is to be explained in another way that simply we can say that a mole is a collection of atoms. Actually one mole of a particular element determines its \[6.022 \times {10^{23}}\] atoms which is the avogadro number. Here we need to divide avogadro number by the number of atoms to find moles.
Complete solution:
We already know that actually mole is a collection of atoms. In a more specific manner , we need to have \[6.022 \times {10^{23}}\] atoms of a particular element in order to complete one mole of those elements.
In this case, as asked in question our aim is to find how many moles of lead are included in \[1.50 \times {10^{12}}\] atoms of lead.
Actually as mentioned above we know that one mole of lead could contain \[6.022 \times {10^{23}}\] atoms of lead. Therefore, as per calculation, in order to get \[1.50 \times {10^{12}}\] atoms of lead , the number of moles to be obtained should be the following method.
\[1.50 \times {10^{12}}Pb\]atoms \[ \times \dfrac{{1mole(Pb)}}{{6.022 \times {{10}^{23}}atoms(Pb)}}\]
\[ = 2.49 \times {10^{ - 12}}\] \[moles\]of lead.
Hence , there are \[2.49 \times {10^{ - 12}}moles\] of lead in \[1.50 \times {10^{12}}\] atoms of lead.
Note:First of all we should differentiate clearly between atom and moles. Then only we can move up with the calculation easily as it is a bit confusing. Next we should be aware about avogadro number as it is the main highlight here to proceed with the calculation and also the avogadro constant should not be written wrong as it is a constant. Main thing is one mole of a particular substance is actually having avogadro number of particles which may be atoms, molecules, or electrons etc.
Complete solution:
We already know that actually mole is a collection of atoms. In a more specific manner , we need to have \[6.022 \times {10^{23}}\] atoms of a particular element in order to complete one mole of those elements.
In this case, as asked in question our aim is to find how many moles of lead are included in \[1.50 \times {10^{12}}\] atoms of lead.
Actually as mentioned above we know that one mole of lead could contain \[6.022 \times {10^{23}}\] atoms of lead. Therefore, as per calculation, in order to get \[1.50 \times {10^{12}}\] atoms of lead , the number of moles to be obtained should be the following method.
\[1.50 \times {10^{12}}Pb\]atoms \[ \times \dfrac{{1mole(Pb)}}{{6.022 \times {{10}^{23}}atoms(Pb)}}\]
\[ = 2.49 \times {10^{ - 12}}\] \[moles\]of lead.
Hence , there are \[2.49 \times {10^{ - 12}}moles\] of lead in \[1.50 \times {10^{12}}\] atoms of lead.
Note:First of all we should differentiate clearly between atom and moles. Then only we can move up with the calculation easily as it is a bit confusing. Next we should be aware about avogadro number as it is the main highlight here to proceed with the calculation and also the avogadro constant should not be written wrong as it is a constant. Main thing is one mole of a particular substance is actually having avogadro number of particles which may be atoms, molecules, or electrons etc.
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