
Molecular orbital theory can be applied to heteronuclear diatomic molecules if the atomic number of the two atoms in the molecule differs by one or two atomic numbers.
If the given statement is true enter 1, else enter 0.
Answer
558k+ views
Hint: The molecular orbital theory is used to define the property of the molecular orbitals formed between the atoms after combining with each other. It can be used for molecules like ${{N}_{2}},\text{ CO, NO, }{{\text{F}}_{2}}$, etc.
Complete answer:
Some properties of the compounds like their relative bond strength, paramagnetic, and diamagnetic nature, etc were explained in the molecular orbital theory developed by Hund and Mullekin in 1932.
The main statement of molecular orbital theory was, “When two atomic orbitals combine or overlap, their identity is lost and leads to a formation of new orbitals. The formed new orbitals are known as molecular orbitals.”
This molecular orbital theory is only applied to the homonuclear molecules or heteronuclear molecules, but the heteronuclear molecules must be the molecules in which the atoms differ only by one or two atomic numbers. There are some conditions for the combinations of atomic orbitals to form molecular orbitals, in which the combining orbitals must have comparable energies. So if the orbitals have a large difference in the energies they will not combine to form molecular orbitals.
The molecular orbital theory is observed in homonucear like ${{H}_{2}}$, $H{{e}_{2}}$, $B{{e}_{2}}$, ${{O}_{2}}$, ${{F}_{2}}$, etc, and in hetero nuclear like $NO$, $CO$, $CN$, etc.
So the given statement in the question is true.
Note:
When two atoms combine, there is the formation of two types of bonding orbitals. These are bonding molecular orbitals and non-bonding molecular orbitals. The molecular orbitals are represented with $\sigma \text{ and }\pi $, the non-bonding orbitals are represented with ${{\sigma }^{*}}\text{ and }{{\pi }^{*}}$.
Complete answer:
Some properties of the compounds like their relative bond strength, paramagnetic, and diamagnetic nature, etc were explained in the molecular orbital theory developed by Hund and Mullekin in 1932.
The main statement of molecular orbital theory was, “When two atomic orbitals combine or overlap, their identity is lost and leads to a formation of new orbitals. The formed new orbitals are known as molecular orbitals.”
This molecular orbital theory is only applied to the homonuclear molecules or heteronuclear molecules, but the heteronuclear molecules must be the molecules in which the atoms differ only by one or two atomic numbers. There are some conditions for the combinations of atomic orbitals to form molecular orbitals, in which the combining orbitals must have comparable energies. So if the orbitals have a large difference in the energies they will not combine to form molecular orbitals.
The molecular orbital theory is observed in homonucear like ${{H}_{2}}$, $H{{e}_{2}}$, $B{{e}_{2}}$, ${{O}_{2}}$, ${{F}_{2}}$, etc, and in hetero nuclear like $NO$, $CO$, $CN$, etc.
So the given statement in the question is true.
Note:
When two atoms combine, there is the formation of two types of bonding orbitals. These are bonding molecular orbitals and non-bonding molecular orbitals. The molecular orbitals are represented with $\sigma \text{ and }\pi $, the non-bonding orbitals are represented with ${{\sigma }^{*}}\text{ and }{{\pi }^{*}}$.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is a periderm How does periderm formation take class 11 biology CBSE

