Question

What is the molecular formula of Strontium Chloride?
A) \[SnC{l_2}\]
B) \[SrC{l_2}\]
C) \[PbC{l_2}\]
D) None of the above

Answer 1

Hint: The strontium is a divalent atom having an ionic symbol \[Sr\]²⁺. We need to know that $Sr$ has $ + 2$ valency whereas chloride has $ - 1$ valency therefore, the formula of strontium chloride turns out to be \[SrC{l_2}\].

Complete step by step answer:
We need to know that the strontium chloride is an inorganic salt containing strontium and chlorine atoms. The salt so formed has no charge on it making it a neutral salt. We also need to know that the \[Sr\] is an alkaline earth metal having atomic number $38$ and we also know that it has its properties intermediate between \[Ba\] and \[Ca\].
Electronic configuration of \[Sr\]: \[\left[ {Kr} \right]5{s^2}\]
Now we discuss about the preparation of strontium chloride as,
\[SrC{l_2}\]can be prepared by using strontium hydroxide and hydrochloric acid:
$Sr{\left( {OH} \right)_2} + 2HCl \to SrC{l_2} + 2{H_2}$ We can be draw the structure of \[SrC{l_2}\] can be represented as:

Let's look at the given options:
Option A) this is an incorrect option as \[SnC{l_2}\] this is tin chloride.
\[Sn\] is an atomic symbol of Tin.
Option B) This is a correct option as \[SrC{l_2}\] is a correct molecular formula for strontium chloride as explained above.
Option C) this is an incorrect option as \[PbC{l_2}\] this is lead chloride.
\[Pb\] is an atomic symbol of lead.
Option D) this is an incorrect option as we got a correct option as option A.

Hence, the correct answer is, ‘Option A’.

Note: The strontium chloride has a molecular weight of \[158.53g/mol\] . We have to know that it is white crystalline powder and an odorless salt. The solubility of \[SrC{l_2}\]is in water and little in alcohol.