What is the molality of pure water at $ 273 $ K?
Answer
525.6k+ views
Hint :We know that the molarity and molality are concentration terms which mean that we can measure the concentration of a solution. Molarity of a solution is equal to the total number of moles of solute per litre of a solution.
Complete Step By Step Answer:
As we know that the molarity of the solution is defined as the number of moles of the solute which is present in one L volume of the solution. We can represent it by the symbol, M. The molarity of the solution is the ratio of the number of moles to the volume of the solution. The number of moles can be calculated by dividing the given mass to the molar mass of the compound.
Both molarity and molality are related to the concentration of the solution. Pure water shows abnormal behaviour at certain temperatures which can be related to concentration. The volume of the solution must be taken in liters only. If the concentration or density of the solute is given in kg or any other unit, it has to be converted into grams because these are the standard units taken for the calculation of Molarity. The concentration of the solution tells the strength of the solution. There are many factors that can be used for calculating the strength of the solution like molarity, molality, normality, mole fraction, ppm, etc. We know that pure water freezes at $ 273 $ K. At $ 273 $ K the molality of pure water is equivalent to the molarity. Let us calculate the molality of pure water at $ 273 $ K here.
$ Molarity=\dfrac{Moles}{Weight\text{ }of\text{ }pure\text{ }water}. $
Molar mass of pure water $ =18.0153\text{ }g/mol $
Number of moles $ =55.348 $
Weight of the solvent $ =0.99707\text{ }kg $
Molality $ =\dfrac{55.348}{0.99707}=55.510\text{ }m $
Therefore, the molality of pure water at $ 273 $ K is $ 55.510m. $
Note :
Remember that the molality of the solution is one of the major factors in calculating the concentration of the solution. There are two factors that are used for the calculation of the molality of the solution, i.e., the number of moles of the solute and the mass of the solvent in kg. When we divide the number of moles of the solute by the mass of the solvent in kg, we get the molality of the solution.
Complete Step By Step Answer:
As we know that the molarity of the solution is defined as the number of moles of the solute which is present in one L volume of the solution. We can represent it by the symbol, M. The molarity of the solution is the ratio of the number of moles to the volume of the solution. The number of moles can be calculated by dividing the given mass to the molar mass of the compound.
Both molarity and molality are related to the concentration of the solution. Pure water shows abnormal behaviour at certain temperatures which can be related to concentration. The volume of the solution must be taken in liters only. If the concentration or density of the solute is given in kg or any other unit, it has to be converted into grams because these are the standard units taken for the calculation of Molarity. The concentration of the solution tells the strength of the solution. There are many factors that can be used for calculating the strength of the solution like molarity, molality, normality, mole fraction, ppm, etc. We know that pure water freezes at $ 273 $ K. At $ 273 $ K the molality of pure water is equivalent to the molarity. Let us calculate the molality of pure water at $ 273 $ K here.
$ Molarity=\dfrac{Moles}{Weight\text{ }of\text{ }pure\text{ }water}. $
Molar mass of pure water $ =18.0153\text{ }g/mol $
Number of moles $ =55.348 $
Weight of the solvent $ =0.99707\text{ }kg $
Molality $ =\dfrac{55.348}{0.99707}=55.510\text{ }m $
Therefore, the molality of pure water at $ 273 $ K is $ 55.510m. $
Note :
Remember that the molality of the solution is one of the major factors in calculating the concentration of the solution. There are two factors that are used for the calculation of the molality of the solution, i.e., the number of moles of the solute and the mass of the solvent in kg. When we divide the number of moles of the solute by the mass of the solvent in kg, we get the molality of the solution.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

What are the major means of transport Explain each class 12 social science CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

Why should a magnesium ribbon be cleaned before burning class 12 chemistry CBSE

