
When is fused with KOH, a colored compound is formed. The product and its color is:
A. , purple green
B. , purple
C. , Brown
D. , Black
Answer
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Hint: As it is given that, the reactants are and KOH. Here both react with each other and form new colored compounds. This reaction occurs in the presence of air and it forms a compound which has color. In this reaction, 2 moles of and 4 moles of KOH react with each other or the formation of colored products.
Complete step by step answer:
When reacts with KOH, it forms a purple green colored product. The reaction is taking place in the presence of air.
Now we see the reaction given as below:
Here Mn has +6 oxidation state and when it reacts with an alkaline compound in the presence of atmospheric oxygen to form purple green colored products.
So that, fused with KOH and formed 2 moles of which is in purple green color and 2 moles of water formed.
Hence option (A) is the correct answer.
Note: Here if the reaction being in the process in the presence of as an oxidizing agent, it gives a dark green compound. Here we remember both reactions in the presence of air and potassium nitrate. The product formed in different colors because here Mn is a transition element which is colorful metal. The equation must be balanced in this reaction. We remember the number of moles in reactants and the number of moles formed in product.
Complete step by step answer:
When
Now we see the reaction given as below:
Here Mn has +6 oxidation state and when it reacts with an alkaline compound in the presence of atmospheric oxygen to form purple green colored products.
So that,
Hence option (A) is the correct answer.
Note: Here if the reaction being in the process in the presence of
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