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What is the maximum number of stereoisomers possible for discodermolide?
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a) ${2^{14}}$
b) ${2^{15}}$
c) ${2^{16}}$
d) ${2^{17}}$

Answer
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Hint: We know that Stereoisomers are the isomers that have the same molecular formula but differ in spatial arrangement of atoms. Stereoisomers can be subdivided into two groups,
-Optical isomers
-Geometrical isomers

Complete step by step solution:
We have to remember that an atom is stereogenic if exchanging any two iotas or gatherings of particles that are bound to it brings about a couple of stereoisomers. Up until this point, particles with no or only one stereogenic iota have been talked about. Frequently the circumstance is more intricate; without a doubt, there can be a few stereogenic particles in an atom.
As we know that a particle with only one stereogenic molecule has just two stereoisomers—the R and S enantiomers. In the event that there are two stereogenic particles in an atom, both can be either R or S. In this way, there are four prospects: RR, SS, RS, and SR.
Three stereogenic particles would prompt eight prospects: RRR, RRS, RSR, SRR, SSR, SRS, RSS, and SSS. The recipe for finding the most extreme number of stereoisomers X will be \[X = {2^n}\] where n is the quantity of stereogenic iotas in the particle.
Discodermolide has 13 chiral carbons and two geometrical centres which means the number of stereoisomers for discodermolide ${2^{15}}$.
Therefore, the option B is correct.

Note: If there is restricted rotation in a molecule there arises geometric isomerism. Geometric isomers are also known as Cis- trans isomerism.
-If the two atoms locked in same side of the molecule then it is called as cis isomers.
-If the two atoms are locked on opposite sides of the molecule then it is called trans isomers.