Match List- $I$ with List- $II$.
List-$I$ List- $II$ a)Read lead p) Lead monoxide b) Litharge q) An ore of lead c) Galena r) An ore of tin d) Cassiterite s) Minium
A.a-r; b-s; c-p; d-q
B.a-r; b-q; c-r ;d-p,q
C.a-s; b-p; c-q; d-r
D.a-r; b-s; c-q; d-p
| List-$I$ | List- $II$ |
| a)Read lead | p) Lead monoxide |
| b) Litharge | q) An ore of lead |
| c) Galena | r) An ore of tin |
| d) Cassiterite | s) Minium |
Answer
595.8k+ views
Hint: We know that ores are very important rocks or sediments that have very important metals, minerals inside it. The valuable metals and minerals can be taken out from the ores by performing different metallurgical processes and purification processes.
Complete step by step solution:
Red lead is a very important inorganic compound. The molecular formula of red lead is \[P{b_3}{O_4}\]. It is mainly used as a red pigment due to its colour. It is used to manufacture batteries and paints. Red lead or \[P{b_3}{O_4}\]is also known as Minimum. So we can write Read lead-Minium, that is a-s.
Litharge is an oxide of lead. The molecular formula of litharge is $PbO$. So from the formula we can say that it leads to monoxide. We can write Litharge-Lead monoxide, that is b-p.
Galena is a very important ore. It is also known as Lead Glance. It is one of the most important ore of lead. The molecular formula of Galena is $PbS$. It is a sulphide ore. So we can write Galena-An ore of lead, that is c-q.
Cassiterite has a molecular formula of $Sn{O_2}$. It is one of the most important ore of tin. So we can write Cassiterite- An ore of tin, that is d-r.
So from the above explanation and discussion it is clear to us that the correct answer of the given question is : Read lead-Minium; Litharge-Lead monoxide; Galena-An ore of lead; Cassiterite- An ore of tin that is the option: C. a-s; b-p; c-q; d-r
Hence, the correct answer is C.
Additional information:
Metallurgy is a very important part of materials science engineering. In metallurgy we learn about different chemical and physical properties of ores,metals and minerals.The concept of metallurgy is used to purify ores and obtain valuable metals and minerals from the ores.
Note: always remember that Red lead, \[P{b_3}{O_4}\] and Minimum are the same thing. Litharge has a molecular formula of $PbO$. Galena is a sulphide ore. The molecular formula of Galena is $PbS$.
Cassiterite or $Sn{O_2}$ is an important ore of tin.
Complete step by step solution:
Red lead is a very important inorganic compound. The molecular formula of red lead is \[P{b_3}{O_4}\]. It is mainly used as a red pigment due to its colour. It is used to manufacture batteries and paints. Red lead or \[P{b_3}{O_4}\]is also known as Minimum. So we can write Read lead-Minium, that is a-s.
Litharge is an oxide of lead. The molecular formula of litharge is $PbO$. So from the formula we can say that it leads to monoxide. We can write Litharge-Lead monoxide, that is b-p.
Galena is a very important ore. It is also known as Lead Glance. It is one of the most important ore of lead. The molecular formula of Galena is $PbS$. It is a sulphide ore. So we can write Galena-An ore of lead, that is c-q.
Cassiterite has a molecular formula of $Sn{O_2}$. It is one of the most important ore of tin. So we can write Cassiterite- An ore of tin, that is d-r.
So from the above explanation and discussion it is clear to us that the correct answer of the given question is : Read lead-Minium; Litharge-Lead monoxide; Galena-An ore of lead; Cassiterite- An ore of tin that is the option: C. a-s; b-p; c-q; d-r
Hence, the correct answer is C.
Additional information:
Metallurgy is a very important part of materials science engineering. In metallurgy we learn about different chemical and physical properties of ores,metals and minerals.The concept of metallurgy is used to purify ores and obtain valuable metals and minerals from the ores.
Note: always remember that Red lead, \[P{b_3}{O_4}\] and Minimum are the same thing. Litharge has a molecular formula of $PbO$. Galena is a sulphide ore. The molecular formula of Galena is $PbS$.
Cassiterite or $Sn{O_2}$ is an important ore of tin.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which is more stable and why class 12 chemistry CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

