Question

Match and find the correct option.

	I		II
(a)	\[pC{O_2​}\]of alveoli of lungs	(i)	\[40mmHg\]
(b)	\[p{O_2}\] of atmospheric air	(ii)	\[95mmHg\]
(c)	\[p{O_2}\] of deoxygenated blood	(iii)	\[104mmHg\]
(d)	\[p{O_2}\] of oxygenated blood	(iv)	\[159mmHg\]

A. a-iii, b-ii, c-i, d-iv
B. a-ii, b-iv, c-iii, d-i
C. a-ii, b-iv, c-i, d-iii
D. a-iii, b-iv, c-i, d-ii

Answer 1

Hint: Partial pressure is associated with the gaseous exchange of respiration i.e, as air travels into the alveoli, water vapour and carbon dioxide are added, and that decreases the partial pressure of oxygen to around\[100mmHg\]in the alveolar gas.

Complete step-by-step answer:
Gas exchange between the air within the pulmonary capillaries and the alveoli happens by diffusion. Gas moves from an area of high partial pressure to an area of low partial pressure, down a partial pressure gradient. In the alveolar air the partial pressure of oxygen is about\[104 - 107mmHg\].
In the alveolar air, \[40mmHg\] is the partial pressure of carbon dioxide and \[104mmHg\] is the partial pressure of oxygen. In oxygenated blood, \[95mmHg\] is the partial pressure of oxygen. In deoxygenated blood, \[40mmHg\] is the partial pressure of oxygen. In the alveoli of the lungs the partial pressure of oxygen is not less than that in the blood. Thus, it favours the diffusion of\[{O_2}\] from alveoli to tissues. In atmospheric air \[159mmHg\] is the partial pressure of oxygen.

Hence the correct answer is D. a-iii, b-iv, c-i, d-ii

	I		II
(a)	\[pC{O_2}\] of alveoli of lungs		\[104mmHg\]
(b)	\[p{O_2}\] of atmospheric air		\[159mmHg\]
(c)	\[p{O_2}\]​ of deoxygenated blood		\[40mmHg\]
(d)	\[p{O_2}\] of oxygenated blood		\[95mmHg\]

Note: In a mixture of gases, the partial pressure is the amount of pressure each gas would exert if it were the only gas in the volume or we can define it as,it is pressure from each of the ingredients of a mixture of gases.