
Let A be a \[2 \times 3\] matrix, whereas B be a \[3 \times 2\] matrix. If det (AB) \[ = 4\], then the value of det (BA) is
A.\[ - 4\]
B.\[2\]
C.\[ - 2\]
D.\[0\]
Answer
519.6k+ views
Hint: In order to solve the question given above, you need to know about matrices and determinants. A matrix is a rectangular table of numbers or expressions which is arranged in rows and columns whereas determinant is a scalar value which is a function of the entries of a square matrix.
Complete step by step solution:
First, we have to create the matrix A and matrix B.
Since A is a \[2 \times 3\] matrix, let it be: \[A = \left[ {\begin{array}{*{20}{c}}
{{a_1}}&{{a_2}}&{{a_3}} \\
{{a_4}}&{{a_5}}&{{a_6}}
\end{array}} \right]\].
Also, B is a \[3 \times 2\] matrix, so, let it be: \[B = \left[ {\begin{array}{*{20}{c}}
{{b_1}}&{{b_2}} \\
{{b_3}}&{{b_4}} \\
{{b_5}}&{{b_6}}
\end{array}} \right]\].
Now we have to find (BA)
For this, we multiply both the matrices.
Now, we have to find the determinant of (BA).
\[\left( {BA} \right) = \left| {\left. {\begin{array}{*{20}{c}}
{{b_1}{a_1} + {b_2}{a_4}}&{{b_1}{a_2} + {b_2}{a_5}}&{{b_1}{a_3} + {b_2}{a_6}} \\
{{b_3}{a_1} + {b_4}{a_4}}&{{b_3}{a_2} + {b_4}{a_5}}&{{b_3}{a_3} + {b_4}{a_6}} \\
{{b_5}{a_1} + {b_6}{a_4}}&{{b_5}{a_2} + {b_6}{a_5}}&{{b_5}{a_3} + {b_6}{a_6}}
\end{array}} \right|} \right.\].
So, the determinant is:
\[\left( {BA} \right) = \left| {\left. {\begin{array}{*{20}{c}}
{{a_1}}&{{a_2}}&{{a_3}} \\
{{a_4}}&{{a_4}}&{{a_6}} \\
0&0&0
\end{array}} \right|} \right. \times \left| {\left. {\begin{array}{*{20}{c}}
{{b_1}}&{{b_2}}&0 \\
{{b_3}}&{{b_4}}&0 \\
{{b_5}}&{{b_6}}&0
\end{array}} \right|} \right.\],
Therefore, from the above calculations, we get that \[\left( {BA} \right) = 0\].
Hence, the correct option is d) \[0\].
So, the correct answer is “Option D”.
Note: While solving questions similar to the one given above you need to keep few concepts in your mind. 1) A rectangular table of symbols or numbers arranged in rows and columns is called a matrix. Plural form is called matrices. 2) In the dimensions of a matrix \[p \times q\], \[p\] is the number of rows whereas \[q\] is the number of columns of a matrix 3) determinant refers to a scalar value that is a function of the entries of a square matrix. Its input is a square matrix and its output is a number.
Complete step by step solution:
First, we have to create the matrix A and matrix B.
Since A is a \[2 \times 3\] matrix, let it be: \[A = \left[ {\begin{array}{*{20}{c}}
{{a_1}}&{{a_2}}&{{a_3}} \\
{{a_4}}&{{a_5}}&{{a_6}}
\end{array}} \right]\].
Also, B is a \[3 \times 2\] matrix, so, let it be: \[B = \left[ {\begin{array}{*{20}{c}}
{{b_1}}&{{b_2}} \\
{{b_3}}&{{b_4}} \\
{{b_5}}&{{b_6}}
\end{array}} \right]\].
Now we have to find (BA)
For this, we multiply both the matrices.
Now, we have to find the determinant of (BA).
\[\left( {BA} \right) = \left| {\left. {\begin{array}{*{20}{c}}
{{b_1}{a_1} + {b_2}{a_4}}&{{b_1}{a_2} + {b_2}{a_5}}&{{b_1}{a_3} + {b_2}{a_6}} \\
{{b_3}{a_1} + {b_4}{a_4}}&{{b_3}{a_2} + {b_4}{a_5}}&{{b_3}{a_3} + {b_4}{a_6}} \\
{{b_5}{a_1} + {b_6}{a_4}}&{{b_5}{a_2} + {b_6}{a_5}}&{{b_5}{a_3} + {b_6}{a_6}}
\end{array}} \right|} \right.\].
So, the determinant is:
\[\left( {BA} \right) = \left| {\left. {\begin{array}{*{20}{c}}
{{a_1}}&{{a_2}}&{{a_3}} \\
{{a_4}}&{{a_4}}&{{a_6}} \\
0&0&0
\end{array}} \right|} \right. \times \left| {\left. {\begin{array}{*{20}{c}}
{{b_1}}&{{b_2}}&0 \\
{{b_3}}&{{b_4}}&0 \\
{{b_5}}&{{b_6}}&0
\end{array}} \right|} \right.\],
Therefore, from the above calculations, we get that \[\left( {BA} \right) = 0\].
Hence, the correct option is d) \[0\].
So, the correct answer is “Option D”.
Note: While solving questions similar to the one given above you need to keep few concepts in your mind. 1) A rectangular table of symbols or numbers arranged in rows and columns is called a matrix. Plural form is called matrices. 2) In the dimensions of a matrix \[p \times q\], \[p\] is the number of rows whereas \[q\] is the number of columns of a matrix 3) determinant refers to a scalar value that is a function of the entries of a square matrix. Its input is a square matrix and its output is a number.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

