
Kellogg is a new cereal formed of a mixture of bran and rice that contains at least $88$ grams of protein and at least $36$ milligrams of iron. Knowing that bran contains $80$ grams of proteins and $40$ milligrams of iron per kilogram, and that rice contains $100$ grams of protein and $30$ milligrams of iron per kilogram. Find the minimum cost of producing this new cereal if bran costs ₹ $5$ per kilogram and rice costs ₹ $4$ per kilogram.
A) ₹ $4.8$
B) ₹ $4.6$
C) ₹ $3.2$
D) ₹ $4$
Answer
544.5k+ views
Hint:
For solving this particular question , we have to form equations from the given information and then try to plot the equation of lines . Find the corner points in the graph then evaluate which corner point gives the minimum cost.
Complete step by step solution:
Let the units of bran be $x$ kg , and the units of rice be $y$ kg. We know that,
We have to minimize $Z = 5x + 4y$
According to the question we have three constraints ,
$
80x + 100y \geqslant 88.......(1) \\
40x + 30y \geqslant 36........(2) \\
x,y \geqslant 0....................(3) \\
$
Now consider $80x + 100y = 88$ ,
we have , $(0,0.8)$ and $(1,0)$ .
$40x + 30y = 36$
we have , $(0,1.2)$ and $(0.9,0)$.
From the table it is clear that $Z$ is minimum at $B\left( {\dfrac{3}{5},\dfrac{2}{5}} \right)$
${Z_{\min }} = 4.6$
Therefore, option $B$ is the correct option.
Note:
Questions similar in nature as that of above can be approached in a similar manner and we can solve it easily. With the help of the graph, we can easily get the corner points , once we get the corner points we can find the point according to the given constraints.
For solving this particular question , we have to form equations from the given information and then try to plot the equation of lines . Find the corner points in the graph then evaluate which corner point gives the minimum cost.
Complete step by step solution:
Let the units of bran be $x$ kg , and the units of rice be $y$ kg. We know that,
| Protein | Iron | Cost | |
| Bran | 80 | 40 | 5 |
| Rice | 100 | 30 | 4 |
| Availability minimum | 88 | 36 |
We have to minimize $Z = 5x + 4y$
According to the question we have three constraints ,
$
80x + 100y \geqslant 88.......(1) \\
40x + 30y \geqslant 36........(2) \\
x,y \geqslant 0....................(3) \\
$
Now consider $80x + 100y = 88$ ,
| x | 0 | 1.1 |
| y | 22/25 | 0 |
we have , $(0,0.8)$ and $(1,0)$ .
$40x + 30y = 36$
| x | 0 | 0.9 |
| y | 1.2 | 0 |
we have , $(0,1.2)$ and $(0.9,0)$.
| Corner points | Z=5x+4y |
| A(1.1,0) | Z=5.5 |
| B(3/5,2/5) | Z=23/5=4.6 |
| C(0,1.2) | Z=4.8 |
From the table it is clear that $Z$ is minimum at $B\left( {\dfrac{3}{5},\dfrac{2}{5}} \right)$
${Z_{\min }} = 4.6$
Therefore, option $B$ is the correct option.
Note:
Questions similar in nature as that of above can be approached in a similar manner and we can solve it easily. With the help of the graph, we can easily get the corner points , once we get the corner points we can find the point according to the given constraints.
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