IUPAC name of \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\]
A) 1-propoxyethane
B) 1-ethoxypropane
C) 2-ethoxypropane
D) 2-propoxyethane
Answer
585.3k+ views
Hint: Aldehydes, ketones, acids, esters, anhydrides, acyl halides, ether, etc are functional groups present in the organic compounds. The presence of the functional group in the organic compounds decides the IUPAC name of the compound. Here, in the question the function group of the given compound is ether.
Complete step-by-step answer:
Here, in the question the compound given is \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\] indicates oxygen atom is bonded to the two alkyl groups hence, the given compound is the ether.
The rules used for IUPAC naming the ethers are as follows:
1)The longest and complex substituent attached to the oxygen is identified and its name is taken as the root name for IUPAC naming of the given ether.
2)The smaller group is taken as the alkoxy substituent while naming.
3)Now, first write the name of the alkoxy substituent and then write the root name.
Here, use the rules given above to find out the IUPAC name of the given compound.
\[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\]
Here, two alkyl groups attached to oxygen atoms are ethyl and propyl groups. As propyl is the three-carbon chain group therefore it is taken as root and ethyl is the two-carbon chain group hence, taken as an alkoxy substituent.
Here, oxygen is attached to the first carbon of the propyl group; the name of the ether is 1-ethoxypropane.
Here, option(A) 1-propoxyethane is incorrect.
Now, option(B) 1-ethoxypropane is the correct answer to the given question.
Option(C)2-ethoxypropane is also an incorrect answer to the question.
Here, option(D)2-propoxyethane is incorrect.
Thus the correct answer is option ‘B’.
Note: Oxidizer is the component used to cause the burning or combustion of the fuel. Oxidizer has also been known as an oxidant or oxidizing agent which causes the oxidation of another substance and itself undergoes the reduction. In the redox reaction, the species which gains the electrons or whose oxidation number is decreasing acts as the oxidizing agent.
Complete step-by-step answer:
Here, in the question the compound given is \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\] indicates oxygen atom is bonded to the two alkyl groups hence, the given compound is the ether.
The rules used for IUPAC naming the ethers are as follows:
1)The longest and complex substituent attached to the oxygen is identified and its name is taken as the root name for IUPAC naming of the given ether.
2)The smaller group is taken as the alkoxy substituent while naming.
3)Now, first write the name of the alkoxy substituent and then write the root name.
Here, use the rules given above to find out the IUPAC name of the given compound.
\[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\]
Here, two alkyl groups attached to oxygen atoms are ethyl and propyl groups. As propyl is the three-carbon chain group therefore it is taken as root and ethyl is the two-carbon chain group hence, taken as an alkoxy substituent.
Here, oxygen is attached to the first carbon of the propyl group; the name of the ether is 1-ethoxypropane.
Here, option(A) 1-propoxyethane is incorrect.
Now, option(B) 1-ethoxypropane is the correct answer to the given question.
Option(C)2-ethoxypropane is also an incorrect answer to the question.
Here, option(D)2-propoxyethane is incorrect.
Thus the correct answer is option ‘B’.
Note: Oxidizer is the component used to cause the burning or combustion of the fuel. Oxidizer has also been known as an oxidant or oxidizing agent which causes the oxidation of another substance and itself undergoes the reduction. In the redox reaction, the species which gains the electrons or whose oxidation number is decreasing acts as the oxidizing agent.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which is more stable and why class 12 chemistry CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

