
IUPAC name of \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\]
A) 1-propoxyethane
B) 1-ethoxypropane
C) 2-ethoxypropane
D) 2-propoxyethane
Answer
549.3k+ views
Hint: Aldehydes, ketones, acids, esters, anhydrides, acyl halides, ether, etc are functional groups present in the organic compounds. The presence of the functional group in the organic compounds decides the IUPAC name of the compound. Here, in the question the function group of the given compound is ether.
Complete step-by-step answer:
Here, in the question the compound given is \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\] indicates oxygen atom is bonded to the two alkyl groups hence, the given compound is the ether.
The rules used for IUPAC naming the ethers are as follows:
1)The longest and complex substituent attached to the oxygen is identified and its name is taken as the root name for IUPAC naming of the given ether.
2)The smaller group is taken as the alkoxy substituent while naming.
3)Now, first write the name of the alkoxy substituent and then write the root name.
Here, use the rules given above to find out the IUPAC name of the given compound.
\[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\]
Here, two alkyl groups attached to oxygen atoms are ethyl and propyl groups. As propyl is the three-carbon chain group therefore it is taken as root and ethyl is the two-carbon chain group hence, taken as an alkoxy substituent.
Here, oxygen is attached to the first carbon of the propyl group; the name of the ether is 1-ethoxypropane.
Here, option(A) 1-propoxyethane is incorrect.
Now, option(B) 1-ethoxypropane is the correct answer to the given question.
Option(C)2-ethoxypropane is also an incorrect answer to the question.
Here, option(D)2-propoxyethane is incorrect.
Thus the correct answer is option ‘B’.
Note: Oxidizer is the component used to cause the burning or combustion of the fuel. Oxidizer has also been known as an oxidant or oxidizing agent which causes the oxidation of another substance and itself undergoes the reduction. In the redox reaction, the species which gains the electrons or whose oxidation number is decreasing acts as the oxidizing agent.
Complete step-by-step answer:
Here, in the question the compound given is \[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\] indicates oxygen atom is bonded to the two alkyl groups hence, the given compound is the ether.
The rules used for IUPAC naming the ethers are as follows:
1)The longest and complex substituent attached to the oxygen is identified and its name is taken as the root name for IUPAC naming of the given ether.
2)The smaller group is taken as the alkoxy substituent while naming.
3)Now, first write the name of the alkoxy substituent and then write the root name.
Here, use the rules given above to find out the IUPAC name of the given compound.
\[{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{ - O - C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{3}}}\]
Here, two alkyl groups attached to oxygen atoms are ethyl and propyl groups. As propyl is the three-carbon chain group therefore it is taken as root and ethyl is the two-carbon chain group hence, taken as an alkoxy substituent.
Here, oxygen is attached to the first carbon of the propyl group; the name of the ether is 1-ethoxypropane.
Here, option(A) 1-propoxyethane is incorrect.
Now, option(B) 1-ethoxypropane is the correct answer to the given question.
Option(C)2-ethoxypropane is also an incorrect answer to the question.
Here, option(D)2-propoxyethane is incorrect.
Thus the correct answer is option ‘B’.
Note: Oxidizer is the component used to cause the burning or combustion of the fuel. Oxidizer has also been known as an oxidant or oxidizing agent which causes the oxidation of another substance and itself undergoes the reduction. In the redox reaction, the species which gains the electrons or whose oxidation number is decreasing acts as the oxidizing agent.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

The compound 2 methyl 2 butene on reaction with NaIO4 class 12 chemistry CBSE

Bacterial cell wall is made up of A Cellulose B Hemicellulose class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

