
Is \[3\] Methyl hexane optically active?
Answer
488.7k+ views
Hint: Hydrocarbons are the compounds consisting of only carbon and hydrogen atoms. Some of the hydrocarbons are optically active. Optically active compounds are compounds that are chiral, and these compounds should not possess any element of symmetry operations.
Complete answer:
Alkanes are the compounds consisting of only carbon and hydrogen atoms. These are also known as paraffins. In alkanes the carbon and hydrogen have only a single bond between them. The hybridization involved in alkanes are \[s{p^3}\].
Given compound is \[3\] Methyl hexane. It has six carbon atoms in its base chain and one carbon in branched chain i.e. substituent. The molecular formula of \[3\] Methyl hexane is \[{C_7}{H_{16}}\].
The structure of \[3\]Methyl hexane will be as follows:
\[C{H_3} - C{H_2} - CH\left( {C{H_3}} \right) - C{H_2} - C{H_2} - C{H_3}\]
The \[{3^{rd}}\] carbon is the central carbon and it is a chiral carbon. Chirality is the property exhibited by the carbon consisting of four different groups. Here \[{3^{rd}}\] carbon consists of four different groups. This compound also does not have any symmetry element like plane of symmetry, axis of symmetry and centre of symmetry.
The given compound \[3\] Methyl hexane does not possess any symmetry element and also it has chiral carbon. Thus, \[3\] Methyl hexane is optically active.
Note:
Optical means light, optically active compounds were able to rotate the plane polarized light. If the compound rotates the plane polarized light towards the right side, then it can be called a d-isomer. If the compound rotates the plane polarized light towards the left side, it can be called as –isomer.
Complete answer:
Alkanes are the compounds consisting of only carbon and hydrogen atoms. These are also known as paraffins. In alkanes the carbon and hydrogen have only a single bond between them. The hybridization involved in alkanes are \[s{p^3}\].
Given compound is \[3\] Methyl hexane. It has six carbon atoms in its base chain and one carbon in branched chain i.e. substituent. The molecular formula of \[3\] Methyl hexane is \[{C_7}{H_{16}}\].
The structure of \[3\]Methyl hexane will be as follows:
\[C{H_3} - C{H_2} - CH\left( {C{H_3}} \right) - C{H_2} - C{H_2} - C{H_3}\]
The \[{3^{rd}}\] carbon is the central carbon and it is a chiral carbon. Chirality is the property exhibited by the carbon consisting of four different groups. Here \[{3^{rd}}\] carbon consists of four different groups. This compound also does not have any symmetry element like plane of symmetry, axis of symmetry and centre of symmetry.
The given compound \[3\] Methyl hexane does not possess any symmetry element and also it has chiral carbon. Thus, \[3\] Methyl hexane is optically active.
Note:
Optical means light, optically active compounds were able to rotate the plane polarized light. If the compound rotates the plane polarized light towards the right side, then it can be called a d-isomer. If the compound rotates the plane polarized light towards the left side, it can be called as –isomer.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

