Question

Ionic equation between copper carbonate and the sulphuric acid question is whether copper carbonate dissociates into its ions or not. According to me, it does not but in some papers, I have seen that it dissociates into $ C{{O}_{3}}^{-2} $ . Explain?

Answer 1

Hint: A reaction between an acid and a base is a neutralization reaction. Copper carbonate acts as a base and sulphuric acid is the acid. A neutralization reaction results in the formation of salt and water. However, the base is a carbonate i.e. copper carbonate.

Complete Step By Step Answer:
When copper carbonate and sulphuric acid react it forms copper sulphate, carbon dioxide, and water. This reaction is also a double displacement reaction as copper is displaced from the carbonate and hydrogen is displaced from the sulphate group. Let’s see the chemical reaction between copper carbonate and sulphuric acid which is as follows:
 $ CuC{{O}_{3(s)}}+{{H}_{2}}S{{O}_{4(aq)}}\text{ }\to \text{ }CuS{{O}_{4(aq)}}+C{{O}_{2(g)}}+{{H}_{2}}{{O}_{(l)}} $
Copper carbonate is a green solution. After the reaction, the solution turns blue. This denotes that the copper ions have been dissociated from the copper (II) carbonate solution. Along with the copper ions you also find sulphate ions in the solution.
Copper carbonate is formed by the reaction between the ions $ C{{u}^{+2}} $ and $ C{{O}_{3}}^{-2} $ . So, $ C{{u}^{+2}} $ from copper carbonate combines with $ SO_{4}^{-2} $ to form Copper (II) sulphate and $ C{{O}_{3}}^{-2} $ forms carbon dioxide. Thus, Copper carbonate does not dissociate into its ions. Only one of its ions is present as it is in the product. The other ion however dissociates even more resulting in other products.

Note:
As we can see that copper is in the carbonate form. This shows that copper consists of carbon dioxide in it. It is stated that when carbonates react with an acid, it results in the formation of carbon dioxide along with salt and water. Also, carbon dioxide is released with brisk effervescence.