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Iodine reacts with concentrated $HN{O_3}$ to yield Y along with other products. The oxidation state of iodine in Y is :a.) 5b.) 3c.) 1d.) 7

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Hint: The Iodine reacts with nitric acid to give $HI{O_3}$ along with nitrogen dioxide and four molecules of water. The oxidation state of the Y is equal to the number of atoms that are present in the molecular formula of Y.

Complete step by step answer:
The reaction of Iodine with concentrated nitric acid is given by -
${I_2} + 10HN{O_3} \to 2HI{O_3} + 10N{O_2} + 4{H_2}O$
The product Y is $HI{O_3}$.
The oxidation state of Y from $HI{O_3}$can be found as -
As the hydrogen = +1
And one Oxygen atom = -2
Thus, three oxygen atoms = -6
And for I be it's ‘x’.
So, the oxidation state can be as-
1+ x + (-6) = 0
1 + x - 6 = 0
‘x’ = 6 - 1
‘x’ = 5

So, the option a.) is the correct answer.

Additional information:
It is essential for the synthesis of thyroid hormones. If a person suffers thyroid related problems, normally doctors refer to iodine containing salt to be consumed. It is even used as a non toxic radiocontrast material.

Note: Iodine is the heaviest stable isotope. It looks like purple black. It is lustrous and is solid at standard conditions. It sublimes with gentle heat. So, there is even mis conception that it does not melt. It can exist in variable oxidation states like -1, +1, +3, +4, +5, +6 and +7. It is a strong acidic oxide.