Question

How do you integrate the given question \[\int {\left( {\sin 2x} \right)} dx\]?

Answer 1

Hint: The given question is of integration and here we can solve the given question by using the standard rule of integration, the given term is of “sin” function, here we know that integration of “sin” function is negative of “cos” function.

Formula used:
 Integration of sin function is :
\[\int {\left( {\sin x} \right)} dx = - \cos x + C\]

Complete step-by-step answer:
The given question is \[\int {\left( {\sin 2x} \right)} dx\]
Here to solve the given question we need to solve it by using the given formulae, on solving we get:
\[ \Rightarrow \int {\left( {\sin 2x} \right)} dx = \dfrac{{\cos 2x}}{{ - 2}} + C\]
Hence we got the solution for the given question.

Additional Information:
To solve the given question here we have used the standard formulae of the integration of sin function, to get the solution, and to cross check the answer we can differentiate the solution of the given question, and if the solution obtained matches with the given question then the solution is correct.

Note: To solve the question of integration we need to first see the variable given in the question, here in the integration method we have different formulae for different terms, and accordingly we need to use the formulae in order to get the correct integration of the question. And accordingly we have found the correct integration of the given question.