
Increasing the internal energy of a system ________ the Helmholtz free energy at constant TS.
(A) increases
(B) Decreases
(C) remains constant
(D) none of these
Answer
570.6k+ views
Hint: For this problem, we have to study the equation of Helmholtz free energy that is given by $A =$ $U - TS$ here, $A$ is considered as the Helmholtz free energy, $U$ is considered as the internal energy, $T$ is the temperature and $S$ is the enthalpy.
Complete step by step solution:
- In the given question, we have to explain that when the internal energy increases then what is the effect on Helmholtz free energy.
- As we know that the Helmholtz free energy is used to measure the work done by the system at constant temperature and volume.
- As we know that the Helmholtz free energy gives a relationship between internal energy, the temperature in Kelvin and enthalpy i.e.
$A =$ $U - TS$
- Here, $A$ is denoted by the Helmholtz free energy, $U$ represents internal energy, $T$ represents temperature and $S$ represents the enthalpy.
- Now, it is given in the question that TS is constant which it does not change under various conditions.
- So, when the internal energy will change, it will directly affect the Helmholtz free energy only.
- That's why when we increase the internal energy of the system, the Helmholtz free energy also increases and vice versa.
Therefore, option (A) is the correct answer.
Note: In the problem, the enthalpy tells us the amount of internal energy that is required to generate a system which is given by $H =$ $U + PV$ here, $U$ represents the internal energy and $P$ & $V$ represents the pressure and volume.
Complete step by step solution:
- In the given question, we have to explain that when the internal energy increases then what is the effect on Helmholtz free energy.
- As we know that the Helmholtz free energy is used to measure the work done by the system at constant temperature and volume.
- As we know that the Helmholtz free energy gives a relationship between internal energy, the temperature in Kelvin and enthalpy i.e.
$A =$ $U - TS$
- Here, $A$ is denoted by the Helmholtz free energy, $U$ represents internal energy, $T$ represents temperature and $S$ represents the enthalpy.
- Now, it is given in the question that TS is constant which it does not change under various conditions.
- So, when the internal energy will change, it will directly affect the Helmholtz free energy only.
- That's why when we increase the internal energy of the system, the Helmholtz free energy also increases and vice versa.
Therefore, option (A) is the correct answer.
Note: In the problem, the enthalpy tells us the amount of internal energy that is required to generate a system which is given by $H =$ $U + PV$ here, $U$ represents the internal energy and $P$ & $V$ represents the pressure and volume.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Why is steel more elastic than rubber class 11 physics CBSE

What is boron A Nonmetal B Metal C Metalloid D All class 11 chemistry CBSE

What is Environment class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

How many squares are there in a chess board A 1296 class 11 maths CBSE

