
In the reaction the product E is:
(A)
(B)
(C)
(D)
Answer
566.7k+ views
Hint: The given initial compound is p-toluidine and is a primary amine. The reactant $NaN{O_2}/HCl$ causes diazotization of the primary amine and leads to the formation of its corresponding diazonium salt. Then its reaction with CuCN or KCN causes the replacement of the diazonium group with the cyano group.
Complete step by step answer:
In this question we need to go step by step for each reactant and first find D and then E.
-So, let us begin by finding D.
We know that the initial given compound is p-toluidine (${H_3}C - {C_6}{H_4} - N{H_2}$) and it is reacted with $NaN{O_2}/HCl$ which are responsible for diazotization reaction.
The diazotization reaction is a reaction where a primary aromatic amine is converted to its corresponding diazonium salt by the use of nitrous acid and some other acid.
So, p-toluidine (${H_3}C - {C_6}{H_4} - N{H_2}$) on reaction with $NaN{O_2}/HCl$, leads to the formation of its corresponding diazonium salt which is compound (D). This compound (D) is 4-methyl benzenediazonium chloride. The reaction is shown below:
Now (D) 4-methylbenzenediazonium chloride is reacted with CuCN or KCN. CuCN or KCN has the ability to replace the diazonium group with the cyano group. So when we react with 4-methyl benzenediazonium chloride with CuCN or KCN it replaces the diazonium group with cyano group which leads to the formation of 4-methyl benzonitrile. Hence the final product (E) is 4-methyl benzonitrile. The reaction is shown below:
-Hence we can conclude that (E) is 4-methyl benzonitrile.
(C)
So, the correct answer is “Option C”.
Note: The diazonium salts are unreactive and hence serve as important synthetic reagents for the formation of dyes and in organic substituents. They can undergo coupling reactions for the formation of azo dyes and also electrophilic substitution reactions for the introduction of functional groups.
Complete step by step answer:
In this question we need to go step by step for each reactant and first find D and then E.
-So, let us begin by finding D.
We know that the initial given compound is p-toluidine (${H_3}C - {C_6}{H_4} - N{H_2}$) and it is reacted with $NaN{O_2}/HCl$ which are responsible for diazotization reaction.
The diazotization reaction is a reaction where a primary aromatic amine is converted to its corresponding diazonium salt by the use of nitrous acid and some other acid.
So, p-toluidine (${H_3}C - {C_6}{H_4} - N{H_2}$) on reaction with $NaN{O_2}/HCl$, leads to the formation of its corresponding diazonium salt which is compound (D). This compound (D) is 4-methyl benzenediazonium chloride. The reaction is shown below:
Now (D) 4-methylbenzenediazonium chloride is reacted with CuCN or KCN. CuCN or KCN has the ability to replace the diazonium group with the cyano group. So when we react with 4-methyl benzenediazonium chloride with CuCN or KCN it replaces the diazonium group with cyano group which leads to the formation of 4-methyl benzonitrile. Hence the final product (E) is 4-methyl benzonitrile. The reaction is shown below:
-Hence we can conclude that (E) is 4-methyl benzonitrile.
(C)
So, the correct answer is “Option C”.
Note: The diazonium salts are unreactive and hence serve as important synthetic reagents for the formation of dyes and in organic substituents. They can undergo coupling reactions for the formation of azo dyes and also electrophilic substitution reactions for the introduction of functional groups.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

