
In the $HCl$ molecule, the separation between the nuclei of the two atoms is about $1.27\mathop A\limits^o $. Find the approximate location of the COM of the molecule, given that a chlorine atom is about 35.5 times as massive as a hydrogen atom and nearly all the mass of an atom is concentrated in its nucleus.
Answer
570.9k+ views
Hint: In this question, we need to evaluate the approximate location of the COM of the molecule such that chlorine atom is about 35.5 times as massive as a hydrogen atom and nearly all the mass of an atom is concentrated in its nucleus. For this, we will assume the mass of hydrogen to be one unit, then find out the mass of the chlorine atom. Use the formula for COM to calculate the position of COM relative to any of the two atoms. Neglect the mass of the electron as said in the question above.
Complete step by step answer:
Let the mass of hydrogen atom be $1amu$
Then mass of chlorine atom will be $35.5amu$
Here one $amu$ means the mass of ${\left( {\dfrac{1}{{12}}} \right)^{th}}$ of Carbon$ - 12$ atom
For ease of calculation, we assume that both the atoms are situated in x axis.
For simplicity let us assume the chlorine atom to be at origin. Therefore the coordinates of chlorine atom will be $(0,0)$
Given the atomic separation to be
Thus the coordinate of hydrogen will be $(1.27,0)$
Now we apply the formula for COM of two masses
Thus COM will be
$
COM = \dfrac{{1.27}}{{1 + 35.5}} \\
= \dfrac{{1.27}}{{36.5}} \\
= 0.036\mathop A\limits^o \\
$
Thus, the COM of the two molecules will be located at a distance from the chlorine atom.
Note:
In the above solution there is no rule to assume the atoms at x-axis or the chlorine atom to be at origin, it totally depends on the personal perspective point of view.
Students can assume any other frame as well. A hydrogen atom and nearly all the mass of an atom is concentrated in its nucleus.
Complete step by step answer:
Let the mass of hydrogen atom be $1amu$
Then mass of chlorine atom will be $35.5amu$
Here one $amu$ means the mass of ${\left( {\dfrac{1}{{12}}} \right)^{th}}$ of Carbon$ - 12$ atom
For ease of calculation, we assume that both the atoms are situated in x axis.
For simplicity let us assume the chlorine atom to be at origin. Therefore the coordinates of chlorine atom will be $(0,0)$
Given the atomic separation to be
Thus the coordinate of hydrogen will be $(1.27,0)$
Now we apply the formula for COM of two masses
Thus COM will be
$
COM = \dfrac{{1.27}}{{1 + 35.5}} \\
= \dfrac{{1.27}}{{36.5}} \\
= 0.036\mathop A\limits^o \\
$
Thus, the COM of the two molecules will be located at a distance from the chlorine atom.
Note:
In the above solution there is no rule to assume the atoms at x-axis or the chlorine atom to be at origin, it totally depends on the personal perspective point of view.
Students can assume any other frame as well. A hydrogen atom and nearly all the mass of an atom is concentrated in its nucleus.
Recently Updated Pages
Complete reduction of benzene diazonium chloride with class 12 chemistry CBSE

How can you identify optical isomers class 12 chemistry CBSE

The coating formed on the metals such as iron silver class 12 chemistry CBSE

Metals are refined by using different methods Which class 12 chemistry CBSE

What do you understand by denaturation of proteins class 12 chemistry CBSE

Assertion Nitrobenzene is used as a solvent in FriedelCrafts class 12 chemistry CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

RNA and DNA are chiral molecules their chirality is class 12 chemistry CBSE

