
In the below reaction, the reactivity of alcohols is;
$ROH + HX \to RX + {H_2}O$ ;
A) \[Tertiary{\text{ }} > {\text{ }}secondary{\text{ }} > {\text{ }}primary\]
B) \[Tertiary{\text{ }} < {\text{ }}secondary{\text{ }} < {\text{ }}primary\]
C) \[Tertiary{\text{ }} > {\text{ }}primary{\text{ }} > {\text{ }}secondary\]
D) \[Secondary{\text{ }} > {\text{ }}primary{\text{ }} > {\text{ }}tertiary\]
Answer
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Hint: Alcohols are compounds in which a hydroxyl (– OH) group is attached to saturated carbon atom.
General Formula: $R - OH$
Monohydric alcohols are classified as primary (1°) secondary (2°), or tertiary (3°), depending upon whether the –OH group is attached to a primary, a secondary, or a tertiary carbon.
Complete step by step answer:Alcohols are reactive compounds. They are attacked by polar or ionic reagents. This is because:
The C–O and O–H bonds of the alcohols are polar since oxygen is highly electronegative.
They oxygen atoms of alcohols is an electron-rich centre because it has two unshared pairs of electrons
Alcohols react with hydrogen (\[HX\]) to form the corresponding alkyl halides
Eg; $C{H_3}C{H_2}OH + HBr \to C{H_3}C{H_2}Br + {H_2}O$
In general, tertiary alcohols react rapidly with hydrogen halides; secondary alcohols react somewhat slower; and primary alcohols, even more slowly.
The reaction is acid catalyzed. Alcohols react with the strongly acidic hydrogen halides \[HCl,{\text{ }}HBr\] , and {\text{ }}HI\], but they do not react with non acidic \[NaCl,{\text{ }}NaBr,{\text{ }}or{\text{ }}NaI\] . Primary and secondary alcohols can be converted to alkyl chlorides and bromides by allowing them to react with a mixture of a sodium halide and sulfuric acid:
The order of reactivity of alcohols is \[3^\circ > 2^\circ > 1^\circ \] methyl.
So,Option “A” is correct.
Note: The order of reactivity of hydrogen halides\[is{\text{ }}HI{\text{ }} > {\text{ }}HBr{\text{ }} > {\text{ }}HCl\] . \[HCl\] reacts only in the presence of a catalyst anhydrous\[(ZnC{l_2})\] .No catalyst is required in the case of \[HBr{\text{ }}or{\text{ }}HI\].
Primary alcohols react with hydrogen halides by an \[{S_N}1\] mechanism.
General Formula: $R - OH$
Monohydric alcohols are classified as primary (1°) secondary (2°), or tertiary (3°), depending upon whether the –OH group is attached to a primary, a secondary, or a tertiary carbon.
Complete step by step answer:Alcohols are reactive compounds. They are attacked by polar or ionic reagents. This is because:
The C–O and O–H bonds of the alcohols are polar since oxygen is highly electronegative.
They oxygen atoms of alcohols is an electron-rich centre because it has two unshared pairs of electrons
Alcohols react with hydrogen (\[HX\]) to form the corresponding alkyl halides
Eg; $C{H_3}C{H_2}OH + HBr \to C{H_3}C{H_2}Br + {H_2}O$
In general, tertiary alcohols react rapidly with hydrogen halides; secondary alcohols react somewhat slower; and primary alcohols, even more slowly.
The reaction is acid catalyzed. Alcohols react with the strongly acidic hydrogen halides \[HCl,{\text{ }}HBr\] , and {\text{ }}HI\], but they do not react with non acidic \[NaCl,{\text{ }}NaBr,{\text{ }}or{\text{ }}NaI\] . Primary and secondary alcohols can be converted to alkyl chlorides and bromides by allowing them to react with a mixture of a sodium halide and sulfuric acid:
The order of reactivity of alcohols is \[3^\circ > 2^\circ > 1^\circ \] methyl.
So,Option “A” is correct.
Note: The order of reactivity of hydrogen halides\[is{\text{ }}HI{\text{ }} > {\text{ }}HBr{\text{ }} > {\text{ }}HCl\] . \[HCl\] reacts only in the presence of a catalyst anhydrous\[(ZnC{l_2})\] .No catalyst is required in the case of \[HBr{\text{ }}or{\text{ }}HI\].
Primary alcohols react with hydrogen halides by an \[{S_N}1\] mechanism.
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