
In semiconductor physics, what is meant by amplifier?
Answer
581.4k+ views
Hint: A transistor has three doped regions and two junctions when its emitter-base junction is forward bias and collector-base junction is reverse biased, it works (in active region) as an amplifier. It is a current sensitive device.
Complete step by step answer:
The amplifier is an electronic device which increases the strength of the weak signal. Amplifier magnifier or amplifies the voltage or current level of a weak signal. Most of the electronic equipment has an amplifier in one form or another. The transistor is a current sensitive device and it has large current gain $\beta $ when operated in an active region.
For a transistor to work as an amplifier, E-B junction should be forward biased and C-B junction should be reverse biased. The voltage source ${{V}_{BB}}\text{ and }{{V}_{CC}}$ provides the necessary bias. The signal voltage ${{V}_{i}}$ which is to be amplified, is applied between base and emitter. E amplified voltage ${{V}_{0}}$ gets developed across the load resistor ${{R}_{L}}$. When the input signal varies slightly, the base current varies which produces a large change in collector current. When this collector current flows through load resistance ${{R}_{L}}$, we get amplified voltage across ${{R}_{L}}\left( {{V}_{0}}=\vartriangle {{I}_{C}}.{{R}_{L}} \right)$
$\begin{align}
& i.e.{{V}_{0}}=\vartriangle {{I}_{C}}.{{R}_{L}} \\
& {{V}_{0}}=\beta \vartriangle {{I}_{B}}.{{R}_{L}}\because \vartriangle {{I}_{C}}=\beta \vartriangle {{I}_{B}} \\
\end{align}$
And we know that $\beta $ is current gain, which is always greater than $50$. By proper designing, $\text{(i}\text{.e}\text{. choosing }\beta \text{ and }{{\text{R}}_{L}})$ we can amplify the input signal by the desired amount. Amplifier voltage gain $\left( {{A}_{v}} \right)$ is defined as the ratio of the output voltage to the input voltage.
Note:
Common base amplifier produces voltage amplification but not current amplification. The amplified voltage is in phase with the input. Common emitter amplifier produces voltage as well as current amplification, but the amplified voltage is ${{180}^{0}}$ out of phase than the input voltage. For amplification action of a transistor, the emitter-base junction must be forward biased and collector-base junction must be reverse biased irrespective of the configuration of the transistor.
Complete step by step answer:
The amplifier is an electronic device which increases the strength of the weak signal. Amplifier magnifier or amplifies the voltage or current level of a weak signal. Most of the electronic equipment has an amplifier in one form or another. The transistor is a current sensitive device and it has large current gain $\beta $ when operated in an active region.
For a transistor to work as an amplifier, E-B junction should be forward biased and C-B junction should be reverse biased. The voltage source ${{V}_{BB}}\text{ and }{{V}_{CC}}$ provides the necessary bias. The signal voltage ${{V}_{i}}$ which is to be amplified, is applied between base and emitter. E amplified voltage ${{V}_{0}}$ gets developed across the load resistor ${{R}_{L}}$. When the input signal varies slightly, the base current varies which produces a large change in collector current. When this collector current flows through load resistance ${{R}_{L}}$, we get amplified voltage across ${{R}_{L}}\left( {{V}_{0}}=\vartriangle {{I}_{C}}.{{R}_{L}} \right)$
$\begin{align}
& i.e.{{V}_{0}}=\vartriangle {{I}_{C}}.{{R}_{L}} \\
& {{V}_{0}}=\beta \vartriangle {{I}_{B}}.{{R}_{L}}\because \vartriangle {{I}_{C}}=\beta \vartriangle {{I}_{B}} \\
\end{align}$
And we know that $\beta $ is current gain, which is always greater than $50$. By proper designing, $\text{(i}\text{.e}\text{. choosing }\beta \text{ and }{{\text{R}}_{L}})$ we can amplify the input signal by the desired amount. Amplifier voltage gain $\left( {{A}_{v}} \right)$ is defined as the ratio of the output voltage to the input voltage.
Note:
Common base amplifier produces voltage amplification but not current amplification. The amplified voltage is in phase with the input. Common emitter amplifier produces voltage as well as current amplification, but the amplified voltage is ${{180}^{0}}$ out of phase than the input voltage. For amplification action of a transistor, the emitter-base junction must be forward biased and collector-base junction must be reverse biased irrespective of the configuration of the transistor.
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