Question

In Grasshopper, rosy body color is caused by a recessive mutation. The wild type of body color is green. If the body color is on the X chromosome, what kind of progeny would be obtained from matting between a rosy female and a wild type male?
A. All the daughters will be green and all the son will be rosy
B. $50\% $daughters are green and $50\% $son are rosy
C. All offspring will be green irrespective of their sex
D. All offspring will be rosy irrespective of their sex

Answer 1

Hint:- With recessive gene mutations on the X chromosome, typically no one but folks can build up the ailment since they have just a single X chromosome. Young ladies have two X chromosomes — since they have a back-up duplicate of another X chromosome, they don't generally show highlights of X-connected conditions.

Complete Answer:-Recessive mutations require two transformed duplicates for the ailment to create. Passive hereditary maladies are regularly not found in each age of an influenced family. The guardians of an influenced individual are for the most part transporters: unaffected individuals who have a duplicate of a changed quality. If the two guardians are transporters of the equivalent transformed quality and both pass it to the kid, the youngster will be influenced. Legacy designs contrast for qualities on sex (chromosomes X and Y) contrasted with qualities situated on autosomes, non-sex (chromosomes numbers 1-22). This is because of the way that, by and large, females convey two X chromosomes (XX), while guys convey one X and one Y chromosome (XY). Hence, females convey two duplicates of every X-connected quality, however, guys convey just one duplicate of every one of X-connected and Y-connected qualities. Females convey no duplicates of Y-connected qualities.
Leave the recessive mutant chromosome alone meant by X'
A female can show ruddy shading just if it is available on both sex chromosomes (X'X') while (X'X) female would show green tone and go about as transporter of the recessive mutant.
A cross between wild sort male (XY) and ruddy female (X'X') will give X'X, X'X, X'Y, X'Y,i.e., half transporter females and half influenced guys.
In this way, the right answer is' All the daughters will be green and all the sons will be rosy.'

Note:- A recessive mutation is one in which the two alleles must be freak all together for the freak aggregate to be watched; that is, the individual must be homozygous for the freak allele to show the freak aggregate.