
In each pair of triangles in the following figure, parts bearing identical marks are congruent .State the test and correspondence of vertices by which triangles in each pair are congruent
\[(a)\]
\[(b)\]
\[(c)\]
\[(d)\]
\[(e)\]
\[(f)\]
Answer
519.3k+ views
Hint: In this question we need to check the conditions of two triangles to be congruent. Basically there are five conditions for two triangles to be congruent they are \[\text{SSS(side side side)}\] , \[\text{SAS(side angle side)}\] , \[\text{ASA(angle side angle)}\] , \[\text{AAS(angle angle side)}\] and \[\text{RHS(right angle-hypotenuse-side)}\] .
Complete answer:
The triangles are said to be congruent if they are of the same shape and size. We may represent the congruence by the symbol \[\widetilde{\text{=}}\] . If the two triangles are congruent then their parameters and areas are equal.
\[\text{(a)}\]
In the above figure in the given \[\vartriangle ABC\] and \[\vartriangle PQR\]
\[\text{AB=PQ}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{AC=QR}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{QC=PR}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{SSS (side side side)}\] property.
THUS, we can say that \[\vartriangle ABC\widetilde{=}\vartriangle PQR\]
\[\text{(b)}\]
In the above figure in the given \[\vartriangle XYZ\] and \[\vartriangle LMN\]
\[\angle \text{Y=}\angle \text{M}\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[XY=LM\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[YZ=MN\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{SAS ( side angle side)}\] property.
THUS, we can say that \[\vartriangle \text{XYZ}\widetilde{=}\vartriangle LMN\]
\[\text{(c)}\]
In the above figure in \[\vartriangle PQR\] and \[\vartriangle STU\]
\[\vartriangle \text{QPR=}\vartriangle T\text{SU}\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[\text{PR=ST}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\vartriangle \text{QRP=}\vartriangle T\text{US}\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{ASA (angle side angle)}\] property.
THUS, we can say that \[~\vartriangle PQR\widetilde{=}\vartriangle STU\]
\[\text{(d)}\]
In the above figure in the given \[\vartriangle BAC\] and \[\vartriangle PQR\]
\[\vartriangle BAC~=\vartriangle PQR\] \[\text{(}\] corresponding angles are right angle \[\text{)}\]
\[\text{AB=PQ}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{BC=PR}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{RHS (right angle- hypotenuse side)}\] property.
Thus, we can say that \[\vartriangle BAC~\widetilde{=}\vartriangle PQR\]
\[\text{(e)}\]
In the above figure in the given \[\vartriangle DAB\] and \[\vartriangle DCB\]
\[\vartriangle DAB=\vartriangle DCB\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[\vartriangle ABD\text{=}\vartriangle BCD\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[\text{BD=BD}\] \[\text{(}\] common lines \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{ASA (angle side angle)}\] property.
Thus, we can say that \[\vartriangle DAB\widetilde{=}\vartriangle DCB\]
\[\text{(f)}\]
In the above figure in the given \[\vartriangle LMN\widetilde{=}\vartriangle PNM\]
\[\text{LM=PN}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{LN=PM}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{MN=MN}\] \[\text{(}\] common line \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{SSS (side side side)}\] property.
THUS, we can say that \[\vartriangle LMN\widetilde{=}\vartriangle PNM\] .
Note:
\[\text{SSA(side side angle) }\] does not follow congruence property because the unknown side could be located in two different places and \[\text{AAA(angle angle angle)}\] also not follows the congruence property as both the triangles may be similar but they are not congruent.
Complete answer:
The triangles are said to be congruent if they are of the same shape and size. We may represent the congruence by the symbol \[\widetilde{\text{=}}\] . If the two triangles are congruent then their parameters and areas are equal.
\[\text{(a)}\]
In the above figure in the given \[\vartriangle ABC\] and \[\vartriangle PQR\]
\[\text{AB=PQ}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{AC=QR}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{QC=PR}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{SSS (side side side)}\] property.
THUS, we can say that \[\vartriangle ABC\widetilde{=}\vartriangle PQR\]
\[\text{(b)}\]
In the above figure in the given \[\vartriangle XYZ\] and \[\vartriangle LMN\]
\[\angle \text{Y=}\angle \text{M}\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[XY=LM\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[YZ=MN\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{SAS ( side angle side)}\] property.
THUS, we can say that \[\vartriangle \text{XYZ}\widetilde{=}\vartriangle LMN\]
\[\text{(c)}\]
In the above figure in \[\vartriangle PQR\] and \[\vartriangle STU\]
\[\vartriangle \text{QPR=}\vartriangle T\text{SU}\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[\text{PR=ST}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\vartriangle \text{QRP=}\vartriangle T\text{US}\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{ASA (angle side angle)}\] property.
THUS, we can say that \[~\vartriangle PQR\widetilde{=}\vartriangle STU\]
\[\text{(d)}\]
In the above figure in the given \[\vartriangle BAC\] and \[\vartriangle PQR\]
\[\vartriangle BAC~=\vartriangle PQR\] \[\text{(}\] corresponding angles are right angle \[\text{)}\]
\[\text{AB=PQ}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{BC=PR}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{RHS (right angle- hypotenuse side)}\] property.
Thus, we can say that \[\vartriangle BAC~\widetilde{=}\vartriangle PQR\]
\[\text{(e)}\]
In the above figure in the given \[\vartriangle DAB\] and \[\vartriangle DCB\]
\[\vartriangle DAB=\vartriangle DCB\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[\vartriangle ABD\text{=}\vartriangle BCD\] \[\text{(}\] corresponding angles are equal \[\text{)}\]
\[\text{BD=BD}\] \[\text{(}\] common lines \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{ASA (angle side angle)}\] property.
Thus, we can say that \[\vartriangle DAB\widetilde{=}\vartriangle DCB\]
\[\text{(f)}\]
In the above figure in the given \[\vartriangle LMN\widetilde{=}\vartriangle PNM\]
\[\text{LM=PN}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{LN=PM}\] \[\text{(}\] corresponding sides are equal \[\text{)}\]
\[\text{MN=MN}\] \[\text{(}\] common line \[\text{)}\]
Here all the corresponding sides are equal in length. Hence it follows \[\text{SSS (side side side)}\] property.
THUS, we can say that \[\vartriangle LMN\widetilde{=}\vartriangle PNM\] .
Note:
\[\text{SSA(side side angle) }\] does not follow congruence property because the unknown side could be located in two different places and \[\text{AAA(angle angle angle)}\] also not follows the congruence property as both the triangles may be similar but they are not congruent.
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