
In class A of 25 students, 20 passed with \[60\% \] or more marks; in another class B of 30 students, 24 passed with \[60\% \] or more marks. In which class was a greater fraction of students getting with \[60\% \] or more marks?
Answer
575.4k+ views
Hint: First we will first use the formula of the probability of the given event is given by dividing the number of students passed divided by the total number of students, that is; $P = \dfrac{{{\text{Number of students passed}}}}{{{\text{Total number of students}}}}$ to compare the values of class A and B to find required value.
Complete step by step answer:
First, we will consider Class A,
We are given that there are total 25 students.
We are also given that there are 20 students passed with \[60\% \] or more marks.
We know that the probability of the given event is given by dividing the number of students passed divided by the total number of students, that is; $P = \dfrac{{{\text{Number of students passed}}}}{{{\text{Total number of students}}}}$.
Finding the probability of students passed in Class A from the above formula of probability, we get
\[ \Rightarrow P\left( A \right) = \dfrac{{20}}{{25}}\]
Dividing the numerator and denominator of the above equation by 5, we get
\[ \Rightarrow P\left( A \right) = \dfrac{4}{5}\]
We will now consider Class B,
We are given that there are total 24 students.
We are also given that there are 30 students passed with \[60\% \] or more marks.
We know that the probability of the given event is given by dividing the number of students passed divided by the total number of students, that is; $P = \dfrac{{{\text{Number of students passed}}}}{{{\text{Total number of students}}}}$.
Finding the probability of students passed in Class B from the above formula of probability, we get
\[ \Rightarrow P\left( B \right) = \dfrac{{24}}{{30}}\]
Dividing the numerator and denominator of the above equation by 6, we get
\[ \Rightarrow P\left( B \right) = \dfrac{4}{5}\]
Since the probability of both the classes is the same, so same fraction of students got first class in both classes A and B.
Note: In solving these types of questions, you should be familiar with the formula to find the probability of the students passing and not passing. Some students get confused while applying formulae. One can find the probability for one class instead of both classes and then conclude the wrong answer. The total number of students is to be written in the denominator of the probability.
Complete step by step answer:
First, we will consider Class A,
We are given that there are total 25 students.
We are also given that there are 20 students passed with \[60\% \] or more marks.
We know that the probability of the given event is given by dividing the number of students passed divided by the total number of students, that is; $P = \dfrac{{{\text{Number of students passed}}}}{{{\text{Total number of students}}}}$.
Finding the probability of students passed in Class A from the above formula of probability, we get
\[ \Rightarrow P\left( A \right) = \dfrac{{20}}{{25}}\]
Dividing the numerator and denominator of the above equation by 5, we get
\[ \Rightarrow P\left( A \right) = \dfrac{4}{5}\]
We will now consider Class B,
We are given that there are total 24 students.
We are also given that there are 30 students passed with \[60\% \] or more marks.
We know that the probability of the given event is given by dividing the number of students passed divided by the total number of students, that is; $P = \dfrac{{{\text{Number of students passed}}}}{{{\text{Total number of students}}}}$.
Finding the probability of students passed in Class B from the above formula of probability, we get
\[ \Rightarrow P\left( B \right) = \dfrac{{24}}{{30}}\]
Dividing the numerator and denominator of the above equation by 6, we get
\[ \Rightarrow P\left( B \right) = \dfrac{4}{5}\]
Since the probability of both the classes is the same, so same fraction of students got first class in both classes A and B.
Note: In solving these types of questions, you should be familiar with the formula to find the probability of the students passing and not passing. Some students get confused while applying formulae. One can find the probability for one class instead of both classes and then conclude the wrong answer. The total number of students is to be written in the denominator of the probability.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

