
In a solution containing 0.01 M HCl and 0.1 M \[{H_2}C{O_3}\], ratio of \[\left[ {{H^ + }} \right]\] produced from strong acid and weak acid respectively is 1. Report your answer as \[\dfrac{x}{{500}}\]. Given: \[{K_{a1}}\] & \[{K_{a2}}\] of \[{H_2}C{O_3}\] are \[4 \times {10^{ - 7}}\] &
\[4 \times {10^{ - 11}}\]
Answer
560.1k+ views
Hint: Since HCl is a strong acid and \[{H_2}C{O_3}\] is a weak acid, the ratio of \[\left[ {{H^ + }} \right]\] produced from strong acid and weak acid respectively is given in the question to be 1. \[{K_a}\] is the acid ionization constant which is the equilibrium constant for chemical reactions involving weak acids in aqueous solution. The numerical value of \[{K_a}\] is used to predict the extent of acid dissociation.
Complete step by step Answer:
HCl is a strong Acid
\[\left[ {{H^ + }} \right] = 0.01M\]
\[{H_2}C{O_3}\] is a weak acid
\[\left[ {{H^ + }} \right] = 2 \times {10^{ - 4}}M\]
\[0.01 > > 2 \times {10^{ - 4}}\]
\[{K_{a1}}\] & \[{K_{a2}}\] of \[{H_2}C{O_3}\] are given as,
\[{K_{a1}} = 4 \times {10^{ - 7}}\]
\[{K_{a2}} = 4 \times {10^{ - 11}}\]
For HCl
\[\left[ {{H^ + }} \right] = \sqrt {{K_{a1}}} .c = \sqrt 4 \times {10^{ - 7}} \times 0.1 = \sqrt 4 \times {10^{ - 8}} = 2 \times {10^{ - 4}}\]
Therefore, we neglect \[2 \times {10^{ - 4}}\]
\[\left\{ {{H^ + }} \right\}ratio\dfrac{{0.01}}{{2 \times {{10}^{ - 4}}}} = \dfrac{1}{2} \times {10^{ - 2}} \times {10^4} = 0.5 \times {10^2}\]
Note: According to the Arrhenius theory of acids and bases, when an acid is added to water, it donates an \[{H^ + }\] ion to water to form \[{H_3}{O^ + }\] (often represented by \[{H^ + }\] ). The higher the concentration of \[{H_3}{O^ + }\] (or \[{H^ + }\] ) in a solution, the more acidic the solution is. An Arrhenius base is a substance that generates hydroxide ions, \[O{H^ - }\], in water. The higher the concentration of \[O{H^ - }\] in a solution, the more basic the solution is. Also, a large \[{K_a}\] value indicates a stronger acid (more of the acid dissociates) and small \[{K_a}\] value indicates a weaker acid.
Complete step by step Answer:
HCl is a strong Acid
\[\left[ {{H^ + }} \right] = 0.01M\]
\[{H_2}C{O_3}\] is a weak acid
\[\left[ {{H^ + }} \right] = 2 \times {10^{ - 4}}M\]
\[0.01 > > 2 \times {10^{ - 4}}\]
\[{K_{a1}}\] & \[{K_{a2}}\] of \[{H_2}C{O_3}\] are given as,
\[{K_{a1}} = 4 \times {10^{ - 7}}\]
\[{K_{a2}} = 4 \times {10^{ - 11}}\]
For HCl
\[\left[ {{H^ + }} \right] = \sqrt {{K_{a1}}} .c = \sqrt 4 \times {10^{ - 7}} \times 0.1 = \sqrt 4 \times {10^{ - 8}} = 2 \times {10^{ - 4}}\]
Therefore, we neglect \[2 \times {10^{ - 4}}\]
\[\left\{ {{H^ + }} \right\}ratio\dfrac{{0.01}}{{2 \times {{10}^{ - 4}}}} = \dfrac{1}{2} \times {10^{ - 2}} \times {10^4} = 0.5 \times {10^2}\]
Note: According to the Arrhenius theory of acids and bases, when an acid is added to water, it donates an \[{H^ + }\] ion to water to form \[{H_3}{O^ + }\] (often represented by \[{H^ + }\] ). The higher the concentration of \[{H_3}{O^ + }\] (or \[{H^ + }\] ) in a solution, the more acidic the solution is. An Arrhenius base is a substance that generates hydroxide ions, \[O{H^ - }\], in water. The higher the concentration of \[O{H^ - }\] in a solution, the more basic the solution is. Also, a large \[{K_a}\] value indicates a stronger acid (more of the acid dissociates) and small \[{K_a}\] value indicates a weaker acid.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

