Question

In a series LCR what will be the phase difference between voltage drop across inductor and capacitor ?

Answer 1

Hint:An $LCR$ circuit, also known as a resonant circuit, tuned circuit, or $RLC$ circuit, A type of electrical circuit that consists of an inductor represented by $L$, a capacitor represented by $C$, and a resistor represented by $R$ connected in series or parallel is called as a resonant circuit, $RLC$ circuit, tuned circuit or most commonly an $LCR$ circuit .

Complete step by step answer:
$R$ , $L$ , $C$ are related in series in the series $LCR$ circuit. Let an AC attached to the circuit with a frequency of $w$ $rad$ / $s$ be considered. Since L and C elements are present in the circuit, some reactance can be offered depending on the frequency. So, the reactance can be given by,
Inductive reactance $ = {X_L}$ $ = w \times L$
Capacitive reactance $ = {X_C}$ $ = \dfrac{1}{{wC}}$
$R$ is unaffected since it is not a reactive element.

Based on the circuit's operating frequency, there are three possible modes of operation:
${X_C} > {X_L}$ where the circuit would act as a capacitive circuit. Similarly, to induction, except that the current is ${90^ \circ }$ away from or above the voltage.

${X_L} > {X_c}$ here the circuit acts as an inductive circuit. Current flows through the inductor generates magnetic flux in the opposite direction of the source. When the current flowing at induction is the greatest, the voltage should be zero, and vice versa. As a result, the current is ${90^ \circ }$ below the voltage.
${X_L} = {X_C}$ is the resonance condition.

Thus, depending on the frequency, the phase of the source voltage and current will range from $ - {90^ \circ }$ to $ + {90^ \circ }$.

Note:As capacitors or inductors interact with an alternating current circuit, current and voltage do not peak at the same time. The phase difference is defined as the fraction of the difference in the time between the peaks expressed in degrees.