
In a first order reaction the concentration of reactant decreases from $800\,mol/d{m^3}$ to $50\,mol/d{m^3}$ in $2 \times {10^4}\,\sec $ . The rate constant of reaction in ${\sec ^{ - 1}}$ is:
A) $2.000 \times {10^4}$
B) $3.415 \times {10^{ - 5}}$
C) $1.386 \times {10^{ - 4}}$
D) $2.000 \times {10^{ - 4}}$
Answer
546.3k+ views
Hint: In order to answer this question, you must recall the concepts and formulae of Chemical Kinetics. Use the formula for finding the rate constant of the reaction and then put all the correct values with proper units and then make the calculation accurately, and hence you will get the required answer.
Complete answer:
The rate constant is a proportionality factor in the rate law of chemical kinetics that relates the molar concentration of reactants to reaction rate. It is also known as the reaction rate constant or reaction rate coefficient and is indicated in an equation by the letter k.
Step 1: In this step we will enlist the given quantities:
The Given quantities in the question are:
Time, $t\, = \,$$2 \times {10^4}\,\sec $
Initial concentration of the reactant, $a\, = \,800\,mol/d{m^3}$
Final concentration of the reactant, $a - x\, = \,50\,mol/d{m^3}$
Step 2: In this step we will use the General formula of rate constant and put all the values to find the required value of rate constant:
$k\, = \,\,\frac{{2.303}}{t}{\log _{10}}\frac{a}{{a - x}}$
Put the values from step 1:
$k\, = \,\,\frac{{2.303}}{{2 \times {{10}^4}}}{\log _{10}}\frac{{800}}{{50}}$
$k\, = \,\,1.386 \times {10^{ - 4}}\,\sec $
Hence, we got the required value of rate constant i.e. $k\, = \,\,1.386 \times {10^{ - 4}}\,\sec $
Hence the correct answer is option C.
Note:The rate constant is defined as the proportionality constant which explains the relationship between the molar concentration of the reactants and the rate of a chemical reaction. The rate constant is denoted by k and is also known as reaction rate constant or reaction rate coefficient. It is dependent on the temperature. There are two possible ways to calculate rate constant and they are Using the Arrhenius equation and Using the molar concentrations of the reactants and the order of the reaction.
Complete answer:
The rate constant is a proportionality factor in the rate law of chemical kinetics that relates the molar concentration of reactants to reaction rate. It is also known as the reaction rate constant or reaction rate coefficient and is indicated in an equation by the letter k.
Step 1: In this step we will enlist the given quantities:
The Given quantities in the question are:
Time, $t\, = \,$$2 \times {10^4}\,\sec $
Initial concentration of the reactant, $a\, = \,800\,mol/d{m^3}$
Final concentration of the reactant, $a - x\, = \,50\,mol/d{m^3}$
Step 2: In this step we will use the General formula of rate constant and put all the values to find the required value of rate constant:
$k\, = \,\,\frac{{2.303}}{t}{\log _{10}}\frac{a}{{a - x}}$
Put the values from step 1:
$k\, = \,\,\frac{{2.303}}{{2 \times {{10}^4}}}{\log _{10}}\frac{{800}}{{50}}$
$k\, = \,\,1.386 \times {10^{ - 4}}\,\sec $
Hence, we got the required value of rate constant i.e. $k\, = \,\,1.386 \times {10^{ - 4}}\,\sec $
Hence the correct answer is option C.
Note:The rate constant is defined as the proportionality constant which explains the relationship between the molar concentration of the reactants and the rate of a chemical reaction. The rate constant is denoted by k and is also known as reaction rate constant or reaction rate coefficient. It is dependent on the temperature. There are two possible ways to calculate rate constant and they are Using the Arrhenius equation and Using the molar concentrations of the reactants and the order of the reaction.
Recently Updated Pages
Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Plot a graph between potential difference V and current class 12 physics CBSE

When was the first election held in India a 194748 class 12 sst CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Which of the following is the best conductor of electricity class 12 physics CBSE

How will you obtain OR AND gates from the NAND and class 12 physics CBSE

The good milk producer Indian buffaloes are A Nagpuri class 12 biology CBSE

