In a college, $25\% $ boys and $10\% $ girls offer mathematics. There are $60\% $ girls in the college. If a mathematics student is chosen at random, then the probability that the student is a girl, will be
1)$\dfrac{1}{6}$
2)$\dfrac{3}{8}$
3)$\dfrac{5}{8}$
4)$\dfrac{5}{6}$
Answer
526.2k+ views
Hint: To find the answer, first we will assume that there are only $100$ students in the college, as we are only to find the probability, we can do so and this assumption will also make the calculations easier for us. Then on applying the given conditions of percentage of girls and boys in the college, we can find the number of girls and boys. Then on applying the percentage of girls offering maths among the total number of girls. Similarly, we can find the number of boys who are offering maths among the total number of boys. Then, we can find the total number of students offering maths. So, we can find the probability of girls offering maths among the math students.
Complete step-by-step solution:
Let us assume the total number of students is $100$.
Given, $60\% $ students in the college are girls.
That means, no. of girls $ = 60\% {\text{ of }}100$
$ = \dfrac{{60}}{{100}} \times 100 = 60$
Since, $60\% $ are girls, that means $40\% $ are boys.
Therefore, the no. of boys $ = 40\% {\text{ of 100}}$
$ = \dfrac{{40}}{{100}} \times 100 = 40$
Then, given, $25\% $ of boys offer mathematics.
No. of boys who offer mathematics$ = 25\% {\text{ of 40}}$
$ = \dfrac{{25}}{{100}} \times 40$
$ = 10$
Also, given, $10\% $ of girls offer mathematics.
No. of girls who offer mathematics$ = 10\% {\text{ of 60}}$
$ = \dfrac{{10}}{{100}} \times 60$
$ = 6$
Therefore, the total number of students who offer mathematics$ = 10 + 6 = 16$
Therefore, the probability that a mathematics student chosen at random is a girl$ = \dfrac{{{\text{No}}{\text{. of girl students offering mathematics}}}}{{{\text{Total no}}{\text{. of mathematics students}}}}$
$ = \dfrac{6}{{16}}$
Simplifying, we get,
$ = \dfrac{3}{8}$
Therefore, the probability that a mathematics student chosen at random is a girl is $\dfrac{3}{8}$, the correct option is 2.
Note: We can solve the problem by assuming the number of students to be a variable, say x. The answer would come out to be the same as the percentage of girls in college as well as those opting for Mathematics remain the same as before. We should take care of the calculations while solving such questions.
Complete step-by-step solution:
Let us assume the total number of students is $100$.
Given, $60\% $ students in the college are girls.
That means, no. of girls $ = 60\% {\text{ of }}100$
$ = \dfrac{{60}}{{100}} \times 100 = 60$
Since, $60\% $ are girls, that means $40\% $ are boys.
Therefore, the no. of boys $ = 40\% {\text{ of 100}}$
$ = \dfrac{{40}}{{100}} \times 100 = 40$
Then, given, $25\% $ of boys offer mathematics.
No. of boys who offer mathematics$ = 25\% {\text{ of 40}}$
$ = \dfrac{{25}}{{100}} \times 40$
$ = 10$
Also, given, $10\% $ of girls offer mathematics.
No. of girls who offer mathematics$ = 10\% {\text{ of 60}}$
$ = \dfrac{{10}}{{100}} \times 60$
$ = 6$
Therefore, the total number of students who offer mathematics$ = 10 + 6 = 16$
Therefore, the probability that a mathematics student chosen at random is a girl$ = \dfrac{{{\text{No}}{\text{. of girl students offering mathematics}}}}{{{\text{Total no}}{\text{. of mathematics students}}}}$
$ = \dfrac{6}{{16}}$
Simplifying, we get,
$ = \dfrac{3}{8}$
Therefore, the probability that a mathematics student chosen at random is a girl is $\dfrac{3}{8}$, the correct option is 2.
Note: We can solve the problem by assuming the number of students to be a variable, say x. The answer would come out to be the same as the percentage of girls in college as well as those opting for Mathematics remain the same as before. We should take care of the calculations while solving such questions.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

