
If$y = \dfrac{{1 - x}}{{{x^2}}}$, then $\dfrac{{dy}}{{dx}}$is
A. $\dfrac{2}{{{x^2}}} + \dfrac{2}{{{x^3}}}$
B. \[ - \dfrac{2}{{{x^3}}} + \dfrac{1}{{{x^2}}}\]
C. $ - \dfrac{2}{{{x^2}}} + \dfrac{2}{{{x^2}}}$
D. None of these
Answer
511.2k+ views
Hint: First, we shall analyze the given information so that we are able to solve the problem. Generally in Mathematics, the derivative refers to the rate of change of a function with respect to a variable. Here in this question, we are asked to calculate the first derivative of the given equation. First, we need to split the given equation for our convenience. Then, we need to differentiate the resultant equation. Here, we are applying the power rule of differentiation to find the required answer.
Formula to be used:
The formula for the power rule of differentiation is as follows.
$\dfrac{d}{{dx}}\left( {{x^n}} \right) = n{x^{n - 1}}$
Complete step by step answer:
It is given that $y = \dfrac{{1 - x}}{{{x^2}}}$
We are asked to calculate the derivative of $y$
To find:$\dfrac{{dy}}{{dx}}$
$y = \dfrac{{1 - x}}{{{x^2}}}$
$ = \dfrac{1}{{{x^2}}} - \dfrac{x}{{{x^2}}}$ (Here we splitted the terms)
$ \Rightarrow y = \dfrac{1}{{{x^2}}} - \dfrac{1}{x}$
Now, we shall differentiate the above equation with respect to x.
Thus,$\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {\dfrac{1}{{{x^2}}} - \dfrac{1}{x}} \right)$
We need to separate the terms on the right side of the above equation.
The formula for the power rule of differentiation is as follows.
$\dfrac{d}{{dx}}\left( {{x^n}} \right) = n{x^{n - 1}}$
That is $\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {\dfrac{1}{{{x^2}}}} \right) - \dfrac{d}{{dx}}\left( {\dfrac{1}{x}} \right)$
$ = \dfrac{d}{{dx}}\left( {{x^{ - 2}}} \right) - \dfrac{d}{{dx}}\left( {{x^{ - 1}}} \right)$
$ = - 2{x^{ - 2 - 1}} - \left( { - 1} \right){x^{ - 1 - 1}}$ (Here we applied the power rule of differentiation)
$ = - 2{x^{ - 3}} + {x^{ - 2}}$
$ = - \dfrac{2}{{{x^3}}} + \dfrac{1}{{{x^2}}}$
Hence $\dfrac{{dy}}{{dx}} = \dfrac{{ - 2}}{{{x^3}}} + \dfrac{1}{{{x^2}}}$ .
So, the correct answer is “Option B”.
Note: We often use the power rule to calculate the derivative of a variable raised to a power and the power rule is the most commonly used derivative rule. When we are asked to find the derivation of the given equation, we need to change the given equation for our convenience. Then we need to analyze where we need to apply the derivative formulae and where we need to apply the rule of differentiation while differentiating the given equation.
Formula to be used:
The formula for the power rule of differentiation is as follows.
$\dfrac{d}{{dx}}\left( {{x^n}} \right) = n{x^{n - 1}}$
Complete step by step answer:
It is given that $y = \dfrac{{1 - x}}{{{x^2}}}$
We are asked to calculate the derivative of $y$
To find:$\dfrac{{dy}}{{dx}}$
$y = \dfrac{{1 - x}}{{{x^2}}}$
$ = \dfrac{1}{{{x^2}}} - \dfrac{x}{{{x^2}}}$ (Here we splitted the terms)
$ \Rightarrow y = \dfrac{1}{{{x^2}}} - \dfrac{1}{x}$
Now, we shall differentiate the above equation with respect to x.
Thus,$\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {\dfrac{1}{{{x^2}}} - \dfrac{1}{x}} \right)$
We need to separate the terms on the right side of the above equation.
The formula for the power rule of differentiation is as follows.
$\dfrac{d}{{dx}}\left( {{x^n}} \right) = n{x^{n - 1}}$
That is $\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}\left( {\dfrac{1}{{{x^2}}}} \right) - \dfrac{d}{{dx}}\left( {\dfrac{1}{x}} \right)$
$ = \dfrac{d}{{dx}}\left( {{x^{ - 2}}} \right) - \dfrac{d}{{dx}}\left( {{x^{ - 1}}} \right)$
$ = - 2{x^{ - 2 - 1}} - \left( { - 1} \right){x^{ - 1 - 1}}$ (Here we applied the power rule of differentiation)
$ = - 2{x^{ - 3}} + {x^{ - 2}}$
$ = - \dfrac{2}{{{x^3}}} + \dfrac{1}{{{x^2}}}$
Hence $\dfrac{{dy}}{{dx}} = \dfrac{{ - 2}}{{{x^3}}} + \dfrac{1}{{{x^2}}}$ .
So, the correct answer is “Option B”.
Note: We often use the power rule to calculate the derivative of a variable raised to a power and the power rule is the most commonly used derivative rule. When we are asked to find the derivation of the given equation, we need to change the given equation for our convenience. Then we need to analyze where we need to apply the derivative formulae and where we need to apply the rule of differentiation while differentiating the given equation.
Recently Updated Pages
Complete reduction of benzene diazonium chloride with class 12 chemistry CBSE

How can you identify optical isomers class 12 chemistry CBSE

The coating formed on the metals such as iron silver class 12 chemistry CBSE

Metals are refined by using different methods Which class 12 chemistry CBSE

What do you understand by denaturation of proteins class 12 chemistry CBSE

Assertion Nitrobenzene is used as a solvent in FriedelCrafts class 12 chemistry CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

RNA and DNA are chiral molecules their chirality is class 12 chemistry CBSE

