If you started with 7.461 grams of magnesium metal, how much oxygen would be consumed during combustion?
Answer
558.9k+ views
Hint: The reaction involved in the above question will be: $2Mg+{{O}_{2}}\to 2MgO$. The formulas that can be used are $Moles=\dfrac{\text{Given mass}}{\text{Molecular mass}}$, $\text{ Moles of magnesium x }\dfrac{\text{Moles of oxygen}}{\text{Moles of magnesium in reaction}}$, and take the molecular mass of oxygen not atomic mass of the oxygen.
Complete answer:
The question says that there is the combustion of magnesium takes place, so the reaction will be:
$2Mg+{{O}_{2}}\to 2MgO$
We can see from the equation that 2 moles of magnesium and 1 mole of oxygen produces 2 moles of magnesium oxide. The molar ratio can be written as either $\dfrac{\text{2 mol Mg}}{\text{1 mol }{{\text{O}}_{2}}}$ or $\dfrac{\text{1 mol }{{\text{O}}_{2}}}{\text{2 mol Mg}}$.
We know the atomic mass of magnesium is 24.305 g /mol and the molecular mass of oxygen will be:
2 x 15.99 g /mol = 31.998 g /mol
The value of the given mass of magnesium taken at the starting of the reaction is 7.461 grams, then we can find the number of moles easily by using the formula:
$Moles=\dfrac{\text{Given mass}}{\text{Molecular mass}}$
$Moles=\dfrac{7.461}{24.30}=0.3069736$
So, the moles of magnesium taken in the reaction are 0.3069736 moles. With this, we can calculate the moles of oxygen used by using the formula:
$\text{ Moles of magnesium x }\dfrac{\text{Moles of oxygen}}{\text{Moles of magnesium in reaction}}$
Putting the values, we can write:
$\text{ 0}\text{.3069736 x}\dfrac{1}{2}\text{ = 0}\text{.15348}$
So, the moles of oxygen used in the combustion will be 0.15348 moles.
Since this value is in moles, we have to find the grams of oxygen used. We can find the mass from the moles by multiplying the molecular mass with moles.
$0.15348\text{ x 31}\text{.998 = 4}\text{.911 g}$
Therefore, the amount of oxygen consumed will be 4.911 grams.
Note:
Don’t take the mass of oxygen as 16 because in the reaction molecule of oxygen is taken not the atomic form of oxygen. You have to find the value of oxygen in grams because the value of magnesium in question is taken in grams.
Complete answer:
The question says that there is the combustion of magnesium takes place, so the reaction will be:
$2Mg+{{O}_{2}}\to 2MgO$
We can see from the equation that 2 moles of magnesium and 1 mole of oxygen produces 2 moles of magnesium oxide. The molar ratio can be written as either $\dfrac{\text{2 mol Mg}}{\text{1 mol }{{\text{O}}_{2}}}$ or $\dfrac{\text{1 mol }{{\text{O}}_{2}}}{\text{2 mol Mg}}$.
We know the atomic mass of magnesium is 24.305 g /mol and the molecular mass of oxygen will be:
2 x 15.99 g /mol = 31.998 g /mol
The value of the given mass of magnesium taken at the starting of the reaction is 7.461 grams, then we can find the number of moles easily by using the formula:
$Moles=\dfrac{\text{Given mass}}{\text{Molecular mass}}$
$Moles=\dfrac{7.461}{24.30}=0.3069736$
So, the moles of magnesium taken in the reaction are 0.3069736 moles. With this, we can calculate the moles of oxygen used by using the formula:
$\text{ Moles of magnesium x }\dfrac{\text{Moles of oxygen}}{\text{Moles of magnesium in reaction}}$
Putting the values, we can write:
$\text{ 0}\text{.3069736 x}\dfrac{1}{2}\text{ = 0}\text{.15348}$
So, the moles of oxygen used in the combustion will be 0.15348 moles.
Since this value is in moles, we have to find the grams of oxygen used. We can find the mass from the moles by multiplying the molecular mass with moles.
$0.15348\text{ x 31}\text{.998 = 4}\text{.911 g}$
Therefore, the amount of oxygen consumed will be 4.911 grams.
Note:
Don’t take the mass of oxygen as 16 because in the reaction molecule of oxygen is taken not the atomic form of oxygen. You have to find the value of oxygen in grams because the value of magnesium in question is taken in grams.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

