
If this dipole were kept in a uniform external electric field${E_0}$, diagrammatically represent the position of the dipole in stable and unstable equilibrium and write the expressions for the torque acting on the dipole in both cases.
Answer
503.9k+ views
Hint In this question, the dipole is kept in a uniform electric field. And we have to write the expressions for them in two different cases. So for solving this, we will keep the dipole at two positions and then, will find the dipole at $\theta = {0^ \circ }$ and at$\theta = {180^0}$.
Formula used:
The potential energy of the dipole will be equal to the
$U = - P{E_0}\cos \theta $
And for torque, the formula will be
$\tau = P{E_0}\sin \theta $
Here,
$U$, will be the potential energy of the dipole
$\tau $ , will be the torque
$P$, will be the electric dipole of the dipole moment
${E_0}$, will be the uniform electric field
Complete Step By Step Solution Let us assume that the dipole we are using is kept at two positions namely $\left( a \right)$ and $\left( b \right)$ which is placed in a constant electric field ${E_0}$ as it is shown in the below diagram.
In the first case: When the angle between the dipole and electric field will be zero
Then, the Potential energy of the dipole will be equal to the
$U = - P{E_0}\cos \theta $
Therefore,
$ \Rightarrow U = - P{E_0}\cos {0^ \circ }$
And on simplifying the equation, we get
Since $\cos {0^ \circ } = 1$
$ \Rightarrow U = - P{E_0}$
Therefore, we can say that the dipole will be in stable equilibrium.
Now we will find the torque,
And for torque, the formula will be
$\tau = P{E_0}\sin \theta $
$ \Rightarrow \tau = P{E_0}\sin {0^0}$
$ \Rightarrow \tau = 0$
In the second case: When the angle between the dipole and electric field will be ${180^ \circ }$
Then, the Potential energy of the dipole will be equal to the
$U = - P{E_0}\cos \theta $
Therefore,
$ \Rightarrow U = - P{E_0}\cos {180^ \circ }$
And on simplifying the equation, we get
Since $\cos {180^ \circ } = - 1$
$ \Rightarrow U = P{E_0}$
Therefore, we can say that the dipole will be in unstable equilibrium.
Now we will find the torque,
And for torque, the formula will be
$\tau = P{E_0}\sin \theta $
$ \Rightarrow \tau = P{E_0}\sin {180^0}$
$ \therefore \tau = 0$
Note Stable equilibrium means the lowest potential energy at the equilibrium point. Therefore the stable equilibrium the torque should be zero and the potential energy of the dipole should be minimum. Whereas the unstable equilibrium torque will be zero and the potential energy should be maximum or positive.
Formula used:
The potential energy of the dipole will be equal to the
$U = - P{E_0}\cos \theta $
And for torque, the formula will be
$\tau = P{E_0}\sin \theta $
Here,
$U$, will be the potential energy of the dipole
$\tau $ , will be the torque
$P$, will be the electric dipole of the dipole moment
${E_0}$, will be the uniform electric field
Complete Step By Step Solution Let us assume that the dipole we are using is kept at two positions namely $\left( a \right)$ and $\left( b \right)$ which is placed in a constant electric field ${E_0}$ as it is shown in the below diagram.
In the first case: When the angle between the dipole and electric field will be zero
Then, the Potential energy of the dipole will be equal to the
$U = - P{E_0}\cos \theta $
Therefore,
$ \Rightarrow U = - P{E_0}\cos {0^ \circ }$
And on simplifying the equation, we get
Since $\cos {0^ \circ } = 1$
$ \Rightarrow U = - P{E_0}$
Therefore, we can say that the dipole will be in stable equilibrium.
Now we will find the torque,
And for torque, the formula will be
$\tau = P{E_0}\sin \theta $
$ \Rightarrow \tau = P{E_0}\sin {0^0}$
$ \Rightarrow \tau = 0$
In the second case: When the angle between the dipole and electric field will be ${180^ \circ }$
Then, the Potential energy of the dipole will be equal to the
$U = - P{E_0}\cos \theta $
Therefore,
$ \Rightarrow U = - P{E_0}\cos {180^ \circ }$
And on simplifying the equation, we get
Since $\cos {180^ \circ } = - 1$
$ \Rightarrow U = P{E_0}$
Therefore, we can say that the dipole will be in unstable equilibrium.
Now we will find the torque,
And for torque, the formula will be
$\tau = P{E_0}\sin \theta $
$ \Rightarrow \tau = P{E_0}\sin {180^0}$
$ \therefore \tau = 0$
Note Stable equilibrium means the lowest potential energy at the equilibrium point. Therefore the stable equilibrium the torque should be zero and the potential energy of the dipole should be minimum. Whereas the unstable equilibrium torque will be zero and the potential energy should be maximum or positive.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What happens if Mutations are not corrected class 12 biology CBSE

Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

When was the first election held in India a 194748 class 12 sst CBSE

